经典java面试英文题

1.What is the result when you compile and run the following code?

public class Test{

public void method(){

for(int i=0;i<3;i++){

System.out.print(i);

}

System.out.print(i);

}

}

result: compile error

分析：

i是局部变量。

for循环完成后，i的引用即消失。

2.What will be the result of executing the following code?

Given that Test1 is a class.

class Test1{

public static void main(String[] args){

Test1[] t1 = new Test1[10];

Test1[][] t2 = new Test1[5][];

if(t1[0]==null){

t2[0] = new Test1[10];

t2[1] = new Test1[10];

t2[2] = new Test1[10];

t2[3] = new Test1[10];

t2[4] = new Test1[10];

}

System.out.println(t1[0]);

System.out.println(t2[1][0]);

}

}

result：null null

分析：

new数组后，数组有大小，但值为null

3.What will happen when you attempt to compile and run the following code? class Base{

int i = 99;

public void amethod(){

System.out.println("Base.method()");

}

Base(){

amethod();

}

}

public class Derived extends Base{

int i = -1;

public static void main(String args[]){

Base b = new Derived();

System.out.println(b.i);

b.amethod();

}

public void amethod(){

System.out.println("Derived.amethod()");

}

}

result:

Derived.amethod()

99

Derived.amethod()

解释：

Derived 重写了Base的amethod方法。

故Base构造函数执行时，执行的是Derived中的amethod.

属性的取值，取决于我们定义的变量的类型。上例中我们定义的变量是Base. 但是，如果定义的变量中的属性为private （不能在类外面直接引用，需要在该类中定义public方法，方便在类外部使用），则会被创建的变量所覆盖。

如果其它类型的属性（friendly, protected,public），不会被创建的变量所覆盖。（静态变量和静态常量属于类，不属于对象，因此它们不能被覆盖。）

而对于定义的变量中的方法，则是相反。会被创建的对象所重写。（override）

考点：

这道题考了继承和泛型使用时，属性和方法，的重写问题。

4.What will be the output on compiling/running the following code?

public class MyThread implements Runnable{

String myString = "yes";

public void run(){

this.myString = "no";

}

public static void main(String args[]){

MyThread t = new MyThread();

new Thread(t).start();

for(int i=0;i<10;i++){

System.out.print(t.myString);

}

}

}

result: yes no no no and so on

5.Multiple objects of MyClass (given below) are used in a program that uses multiple Threads to create new integer count. What will happen when other threads use following code?

class MyClass{

static private int myCount =0;

int yourNumber ;

private static synchronized int nextCount(){

return ++myCount;

}

public void setYourNumber(){

yourNumber = nextCount();

}

}

A. the code will give ompilation error.

B. the code will give runtime error.

C. each thread will get a unique number.

D. the uniqueness of the number different Threads can't be guaranteed.

答案：C

6.What is displayed when the following code is compiled and executed?

String s1 = new String("Test");

String s2 = new String("Test");

if(s1==s2) System.out.println("Same");

if(s1.equals(s2)) System.out.println("Equals");

A. Same Equals

B. Same

C. Equals

答案：C

分析：==判断的是（栈）内存地址所对应的值，是否相等

String类的equals方法，判断的是（堆）内存地址所对应的值，是否相等。即：字符串的内容是否相等。

String对象不是基本数据类型，属于引用数据类型。有2块内存（栈内存、堆内存）。栈内存的值，就是堆内存的地址。

基本数据类型只有一块内存（栈内存）。

2个String对象，在堆中对应生成了2个对象。它们在栈内存中的引用地址当然不同。但在堆内存中的值却相同，虽然在堆内存中的地址是不同的（且必须不能相同，因为它们是2个对象）。

7.Which of the following lines will print false?

public class MyClass{

static String s1="I am unique!";

public static void main(String args[]){

String s2 = "I am unique!";

String s3 = new String (s1);

8.System.out.println(s1==s2);

9.System.out.println(s1.equals(s2));

10.System.out.println(s3==s1); // only this line :false

11. System.out.println(s3.equals(s1));

12. System.out.println(TestClass.s4 == s1);

}

}

class TestClass{

static String s4 = "I am unique!";

}

A. line 10 and 12

B. line 12 only

C. line 8 and 10

D.none of these

answer: D

分析：

1、java中String类的对象，一旦生成后，是不可变的（长度不可变、内容也不可变）。除非再新new一个。

2、对于一个String字符串（例如："I am unique!"）来说，虽然它不是new出来的，但是，在第一次使用的时候，有一个匿名的String对象指向了它。

java利用最优化方法：以后如果出现内容相同的String字符，直接把这个引用地址给这个对象，而不是再生成一个String字符。

所以凡是String str_n = "I am unique!"，这种写法的，它们的引用地址是相同的。引用地址所对应的值也相同。

看英文分析：

Strings are immutable objects. That is , a string is read only once the string has been created and initialized.

Java optimizes handling of string literals :

only one anonymous string object is shared by all string literals with the same contents.

Hence, in the above code the string s1,s2 and s4 refer to the same anonymous string object,

initializing with the character string :"I am unique!".

Thus s1==s2 and TestClass.s4 will both return true and obviously s1.equals(s2) will return true.

But creating string objects using the constructor String(String s) creates a new string , hence s3 == s1 will return false.

even though s3.equals(s1) will return true , because s1 and s3 referring to two different stringobjects whose contents are same.

https://www.sodocs.net/doc/253932148.html,/library/quiz/java/blscjp14_q26.htm

8.What is displayed when the following is executed?

class Parent{

private void method1(){

System.out.println("Parent's method1()");

}

public void method2(){

System.out.println("Parent's method2()");

method1();

}

}

class Child extends Parent{

public void method1(){

System.out.println("Child's method1()");

}

public static void main(String args[]){

Parent p = new Child();

p.method2();

}

}

A. compile time error

B. run time error

C. prints: parent's method2() prarent's method1()

D. prints: parent's method2() Child's method1()

answer: C

分析：

在parent中，虽然method1是private的，

但是仍然可以在public的method2中被调用。

而method2又可以被其子类调用。

故方法（或属性）的权限的使用，仅是受使用范围的限制。而不受其使用对象的限制。

如同：把一个成员变量设为private，然后对外提供访问其的public方法。外部仍然可以访问这个private的成员变量。

9.What will happen when you attempt to compile and run the following code snippet?

String str = "Java";

StringBuffer buffer = new StringBuffer(str);

if(str.equals(buffer)){

System.out.println("Both are equal");

}else{

System.out.println("They are so different");

}

A. print: They are so different

B. print: Both are equal

C. compile time error

D. Runtime error

answer: A

解释：equals方法只能比较同是String类型的对象

10.What will be printed when you execute the following code?

class X{

Y b = new Y();

X(){

System.out.print("X");

}

}

class Y{

Y(){

System.out.print("Y");

}

}

public class Z extends X{

Y y = new Y();

Z(){

System.out.print("Z");

}

public static void main(String[] args){

new Z();

}

}

A. Z

B. YZ

C. XYZ

D. YXYZ

answer: D

分析：

Z是从X继承而来。new Z时，先构造X。

1.类在构造方法执行之前，先初始化其成员变量，Y b = new Y();故：首先输出Y

2.然后执行X的构造函数。输出：X

3.在Z自己的构造方法执行之前，先初始化其成员变量，Y y = new Y();输出：Y

4.最后执行Z的构造函数。输出：Z

这道题有2个考点：

1、类在构造方法执行之前，先初始化其成员变量

2、先构造父类，再构造子类。（因为子类从父类继承而来，父类必须先构造出

来）

二、写成程序的运行结果

1、

public class FatherClass{

public FatherClass(){

System.out.println("FatherClass Create");

}

}

public class ChildClass extends FatherClass{

public ChildClass(){

System.out.println("ChildClass Create");

}

public static void main(String[] args){

FatherClass f = new FatherClass();

ChildClass c = new ChildClass();

}

}

运行结果：

FatherClass Create

FatherClass Create

ChildClass Create

分析：

1.1）如果用户重写了构造方法，则new时，必须使用重写的构造方法。否则

报错。

1.2）如果用户没有重写，则系统默认调用参数为空的构造方法。

2.1）子类构造方法中，没有显式调用父类构造方法，则默认调用父类参数为空的构造方法。且父类构造方法必须先于子类构造方法执行。

所以：

FatherClass f = new FatherClass(); //=>输出：FatherClass Create

ChildClass c = new ChildClass();//=>输出：FatherClass CreateChildClass Create

2、

public class OuterInner {

private class InnerClass{

public InnerClass(){

System.out.println("InnerClass Create");

}

}

public OuterInner(){

InnerClass in = new InnerClass();

System.out.println("OuterClass Create");

}

public static void main(String[] args) {

OuterInner o = new OuterInner();

}

}

运行结果：

InnerClass Create OuterClass Create

分析：这道题很普通。

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