9702_s03_ms
June 2003
GCE ADVANCED SUBSIDIARY LEVEL AND ADVANCED LEVEL
MARK SCHEME
MAXIMUM MARK: 40
SYLLABUS/COMPONENT: 9702/01
PHYSICS
Paper 1 (Multiple Choice (AS))
Page 1Mark Scheme Syllabus Paper A/AS LEVEL EXAMINATIONS - JUNE 2003970201
Question Number Key
Question
Number
Key
1B21B 2B22D 3B23B 4A24D 5C25C
6B26B 7C27C 8C28C 9D29B 10D30C
11B31A 12A32B 13D33B 14B34B 15A35C 16C36D 17C37B 18D38C 19B39B 20A40D
June 2003
GCE ADVANCED SUBSIDIARY LEVEL AND ADVANCED LEVEL
MARK SCHEME
MAXIMUM MARK: 60
SYLLABUS/COMPONENT: 9702/02
PHYSICS
Paper 2 (Structured Questions (AS))
A/AS LEVEL EXAMINATIONS - JUNE 2003970202 Categorisation of marks
The marking scheme categorises marks on the MACB scheme.
B marks: These are awarded as independent marks, which do not depend on other marks. For a B-mark to be scored, the point to which it refers must be seen specifically in the candidate’s answer.
M marks: These are method marks upon which A-marks (accuracy marks) later depend. For an
M-mark to be scored, the point to which it refers must be seen in the candidate’s answer. If a candidate fails to score a particular M-mark, then none of the dependent A-marks can be scored.
C marks: These are compensatory method marks which can be scored even if the points to which they refer are not written down by the candidate, providing subsequent working gives evidence that they must have known it. For example, if an equation carries a C-mark and the candidate does not write down the actual equation but does correct working which shows he/she knew the equation, then the
C-mark is awarded.
A marks: These are accuracy or answer marks which either depend on an M-mark, or allow a C-mark to be scored.
Conventions within the marking scheme
BRACKETS
Where brackets are shown in the marking scheme, the candidate is not required to give the bracketed information in order to earn the available marks.
UNDERLINING
In the marking scheme, underlining indicates information that is essential for marks to be awarded.
A/AS LEVEL EXAMINATIONS - JUNE 2003970202
1kg m-3.......................................................................................B1
frequency or count rate or activity or decay constant...................B1
NC-1 or V m-1 or kg m s-2 C-1 etc...................................................B1
momentum or impulse..................................................................B1
(Allow solidus notation and non SI units)
[4]
2(a)(i)
(ii)distance from a (fixed) point.........................................................M1
in a specified direction.................................................................A1 (Allow 1 mark for ‘distance in a given direction’)
(displacement from start is zero if) car at its starting position.....B1[3]
(b)(i)1v2 = u2 +2as
282 = 2 x a x 450 (use of component of 450 scores no marks).....C1
a = 0.87 m s-2...............................................................................A1
(-1 for 1 sig. fig. but once only in the question)
[2]
(i)2v = u + at or any appropriate equation
28 = 0.87t or appropriate substitution...........................................C1
t = 32 s.......................................................................................A1[2]
(i)3E k = ?mv2....................................................................................C1
= ? x 800 x 282
= 3.14 x 105 J...........................................................................A1[2]
(i)4E p = mgh....................................................................................C1
= 800 x 9.8 x 450 sin5...........................................................C1
= 3.07 x 105 J........................................................................A1[3]
(ii)power = energy/time....................................................................C1
=(6.21 x 105)/32.2.............................................................C1
= 1.93 x 104 W..................................................................A1
(power = Fv with F = mg sin scores no marks)
[3]
(iii)some work also done against friction forces.................................M1
location of frictional forces identified............................................A1
(allow reasonable alternatives)
[2] 3(a)(i)ductile...............................................................................B1 (ii)1L shown at end of straight line.....................................................B1
(ii)2reciprocal of gradient of straight line region...............................B1[3]
(b)(i)1circumference = 3p cm or arc = r.............................C1
extension = (6.5/360) x 3p= 1.5 sin (or tan) 6.5..........M1
= 0.17 cm...................................................................A0
(i)2strain = extension/length.............................................................C1
= 0.17/250
= 6.8 x 10-4........................................................................A1[4] (ii)stress = force/area......................................................................C1
= (6.0 x 9.8)/(7.9 x 10-7)....................................................C1
= 7.44 x 107 Pa.................................................................A1[3]
A/AS LEVEL EXAMINATIONS - JUNE 2003970202 (iii)Young modulus = stress/strain....................................................C1
= (7.44 x 107)/(6.8 x 10-4)
= 1.1 x 1011 Pa..................................................A1[2]
(iv)remove extra load and see if pointer returns to original position or
wire returns to original length.......................................................B1[1] 4(a) e.g. both transverse/longitudinal/same type
meet at a point,
[3]
same direction of polarisation, etc.......1 each, max 3.................B3
(allow 1 mark for any condition for observable interference)
(b)(i)1allow 0.3 mm ? 3 mm..................................................................B1
(i)2l = ax/D (allow any subject).........................................................B1
(ii)1separation increased....................................................................B1
less bright....................................................................................B1
(ii)2separation increased....................................................................B1
less bright....................................................................................B1 (ii)3separation unchanged..................................................................B1
fringes brighter.............................................................................B1
[7]
further detail, i.e quantitive aspect in (ii)1 or (ii)2..........................B1
(in (b), do not allow e.c.f. from (b)(i)2)
5(a)(i)resistance= V/I...................................................................................C1
= 6.0/(40 x 10-3)
= 150 W......................................................................A1
(no marks for use of gradient)
(ii)at 8.0 V, resistance = 8.0/(50 x 10-3) = 160 W...............................C1
change = 10 W.............................................................................A1[4]
(b)(i)straight line through origin............................................................M1
passes through I = 40 mA, V = 8.0V............................................A1
(ii)current in both must be 40 mA.....................................................C1
e.m.
f. = 8.0 + 6.0 = 14.0 V...........................................................A1[4] 6(a)(i)curve is not smooth, fluctuations, etc...........................................B1
(ii)curve is same shape or same half-life, not affected by temperature,
etc...............................................................................................B1[2]
(b)(i)134..............................................................................................B1[1]
(ii)a-particle shown as He
4
or as a42...............................................B1
2
nucleon number of Po shown as 216...........................................B1
proton number of Po shown as 84................................................B1
[3]
June 2003
GCE ADVANCED SUBSIDIARY LEVEL AND ADVANCED LEVEL
MARK SCHEME
MAXIMUM MARK: 25
SYLLABUS/COMPONENT: 9702/03
PHYSICS
Paper 3 (Practical (AS))
A/AS LEVEL EXAMINATIONS - JUNE 2003970203
2/1/0 1(a)(iv)% uncertainty in
Accept ?to +1° + 2°(1 mark)
Ratio and percentage ideas correct(1 mark)
3/2/1/0
(d)(i)Measurements
Expect to see at least 6 sets of results (1 mark)
Less than 6 sets does not score this mark
Check a value of T-4. Underline checked value and tick if correct
(1 mark)
Ignore small rounding errors. This mark cannot be awarded if there
are no raw times, number of oscillations measured in a fixed time, or
the stopwatch has been misread. If there is no record of the number
of oscillations then this mark cannot be scored
It may be necessary to refer to page 3 of script for a value of n
Check a value for cos. Underline checked value and tick if correct
(1 mark)
Ignore small rounding errors. Expect to see a correct sign
If either incorrect, write in correct value and -1 eeoo
Minor help given by Supervisor, -1. Major help, then -2
(d)(i)Repeated readings
1 For each value of there must be at least two values of t
An average value does not have to be calculate
(d)(i)At least 10° between the readings of 1
2/1/0
(d)(i)Quality of results
Judge by scatter of points about Examiner line of best fit
6 reasonable trend plots with little scatter(2 marks)
5 trend plots, or some scatter of plots (1 mark)
Large scatter/no trend/wrong quantities plotted(zero)
(d)(i)Column headings
1 Check the 1/T4 column heading only
Quantity and unit (s-4) must be correct
2/1/0
(d)(i)Consistency
Apply to raw values of and t only(one mark each)
Values of must all be given to the nearest degree. Do not allow
tenths of a degree
Values of t must all be given to the nearest 0.1 s or 0.01 s
Do not apply to average values
(d)(ii)Justification of number of sf in cos
1 Answer must relate sf in to sf in cos
Do not allow answers in terms of decimal places
Do not allow vague answers that are given in terms of ‘raw data’
(e)(i)Axes
1 Scales must be such that the plotted points occupy at least half the
graph grid in both the x and y directions (i.e. 4 x 6 in portrait or 6 x 4
in landscape)
Axes must be labelled with the quantity plotted. Ignore units. Do not
allow awkward scales or gaps of more than three large squares
between the scale markings
A/AS LEVEL EXAMINATIONS - JUNE 2003970203
1 (e)(i)Plotting of points
Check a suspect plot. Circle and tick if correct. If incorrect, show
correct position with arrow, and -1. Work to half a small square. All
observations must be plotted
1 (e)(i)Line of best fit
There must be a reasonable balance of points about the line of best
fit
There must be at least 5 plots on the grid for this mark to be awarded
Do not allow a straight line to be drawn through a distinct curve trend
Allow an acceptable curve through a curved trend of points
1 (e)(ii)Determination of gradient
Hypotenuse of ? used must be greater than half the length of the
drawn line
Check the read-offs and ratio. Read-offs must be accurate to half a
small square
Do not allow this mark if a curve has been drawn
1 (e)(ii)y-intercept
The value must be read to half a small square
Do not allow this mark if a curve has been drawn
(f)A = candidate's value of gradient1 (f) B = candidate's value of intercept1 (f)Unit of A and B both correct (s-4)1
1 (g)Measurement of L
The value should be in the range 40 cm + 2 cm. Can be implied in
the working
It may be necessary to refer to the Supervisor's Report
1
(g)Correct method of working to give a value for g in range 9.0 to
11.0 m s-2
A POT error anywhere in the working will not score this mark
1 (g)Sf in g
Allow 2 or 3 sf only. Apply to any value given
A bald value with no working cannot score this mark
1 (g)Unit of g correct (and consistent with other measurements, e.g. L)
There must be a numerical value of g for this mark to be scored
A bald value with no working cannot score this mark
25 marks in total
June 2003
GCE ADVANCED SUBSIDIARY LEVEL AND ADVANCED LEVEL
MARK SCHEME
MAXIMUM MARK: 60
SYLLABUS/COMPONENT: 9702/04
PHYSICS
Paper 4 (Structured Questions (A2 Core))
A/AS LEVEL EXAMINATIONS - JUNE 2003970204 Categorisation of marks
The marking scheme categorises marks on the MACB scheme.
B marks: These are awarded as independent marks, which do not depend on other marks. For a B-mark to be scored, the point to which it refers must be seen specifically in the candidate’s answer.
M marks: These are method marks upon which A-marks (accuracy marks) later depend. For an
M-mark to be scored, the point to which it refers must be seen in the candidate’s answer. If a candidate fails to score a particular M-mark, then none of the dependent A-marks can be scored.
C marks: These are compensatory method marks which can be scored even if the points to which they refer are not written down by the candidate, providing subsequent working gives evidence that they must have known it. For example, if an equation carries a C-mark and the candidate does not write down the actual equation but does correct working which shows he/she knew the equation, then the C-mark is awarded.
A marks: These are accuracy or answer marks which either depend on an M-mark, or allow a
C-mark to be scored.
Conventions within the marking scheme
BRACKETS
Where brackets are shown in the marking scheme, the candidate is not required to give the bracketed information in order to earn the available marks.
UNDERLINING
In the marking scheme, underlining indicates information that is essential for marks to be awarded.
A/AS LEVEL EXAMINATIONS - JUNE 2003970204
1(a)work done in bringing/moving unit mass......................................M1
[2]
from infinity to the point................................................................A1
(use of 1 kg in the definition – max 1/2)
(b)potential at infinity defined as being zero.....................................B1
forces are always attractive..........................................................B1
so work got out in moving to point................................................B1
[3]
(max potential is at infinity – allow 1/3)
(c)(i)φ = -GM/R
change = 6.67 x 10-11 x 6.0 x 1024 x({6.4 x 106}-1- {1.94 x 107}-1).....C2
change = 4.19 x 107 J kg-1 (ignore sign).........................................A1
(ii)?mv2 = mφ................................................................................C1
v2 = 2 x 4.19 x 107 = 8.38 x 107
v = 9150 m s-1..............................................................................A1[5]
(d)acceleration is not constant..........................................................B1[1] 2(a)
(-1 for each error or omission)........................................B2[2]
(b)heat lost by liquid gold = 0.95m x 129 x ?T..................................C1
heat gained (silver) = 0.05m x 235 x (1340 – 300) + 0.05m x 105 000..C1, C1
122.5m?T = 17 470m
?T = 143 K.......................................................................................C1
temperature = 143 + 1340 = 1483 K................................................A1[5]
(c) e.g. thermocouple/resistance thermometer..................................B1[1]
3(a)f0 is at natural frequency of spring (system).................................B1
[2]
this is at the driver frequency.......................................................B1
(allow 1 mark for recognition that this is resonance)
(b)line: amplitude less at all frequencies.........................................B1
peak flatter..........................................................................B1
peak at f0 or slightly below f0................................................B1[3]
(c)(aluminium) sheet cuts the magnetic flux/field..............................B1
(so) currents/e.m.f. induced in the (metal) sheet..........................B1
these currents dissipate energy...................................................M1
less energy available for the oscillations......................................A1
[4]
so amplitude smaller....................................................................A0
(‘current opposes motion of sheet’ scores one of the last two
marks)
4(a)field causes forces on the electrons.............................................M1
and the nucleus in opposite directions.........................................A1
(field causes) electrons (to be) stripped off the atom....................B1[3]
(b)(i)E = Q/4pε0r2.....................................................................................C1
20 x 103 x 102 = Q/(4p x 8.85 x 10-12 x 0.212....................................C1
charge = 9.8 x 10-6 C.......................................................................A1[3]
A/AS LEVEL EXAMINATIONS - JUNE 2003970204 (ii)V = Q/4pε0r
= (9.8 x 10-6)/(4p x 8.85 x 10-12 x 0.21)........................................C1
= 4.2 x 105 V................................................................................A1[2]
(c) e.g. sphere not smooth, humid air, etc............................................B1[1] 5(a)centripetal force = mv2/r...................................................................B1
magnetic force F = Bqv....................................................................B1
(hence) mv2/r = Bqv.........................................................................B1
r = mv/Bq.........................................................................................A0[3]
(b)r a/r b = (m a/m b) x (q b/q a)...................................................................C1
= (4 x 1.66 x 10-27)/(9.11 x 10-31 x 2)
= 3.64 x 103...............................................................................A2[3]
(c)(i)r a= (4 x 1.66 x 10-27 x 1.5 x 106)/(1.2 x 10-3 x 2 x 1.6 x 10-19)
= 25.9 m......................................................................................A2 (ii)r b = 25.9 x 3.64 x 103 = 7.13 x 10-3 m..............................................A1[3]
(d)(i)deflected upwards............................................................................B1
but close to original direction...........................................................B1 (ii)opposite direction to a-particle and ‘through side’...........................B1[3] 6(a)greater binding energy gives rise to release of energy...................M1
so must be yttrium...........................................................................A1[2]
(b)probability of decay.........................................................................M1
of a nucleus per unit time.................................................................A1[2]
(c)(i)1 A = l N..............................................................................................C1
3.7 x 106 x 365 x 24 x 3600 = 0.025N..............................................C1
N = 4.67 x 1015.................................................................................A1[3]
(i)2mass = 0.09 x (4.67 x 1015)/(6.02 x 1023).........................................C1
= 6.98 x 10-10 kg......................................................................A1[2] (ii)A = A0 e-l t
A/A0 = e-0.025t....................................................................................C1
= 0.88......................................................................................A1[2]
June 2003
GCE ADVANCED SUBSIDIARY LEVEL AND ADVANCED LEVEL
MARK SCHEME
MAXIMUM MARK: 30
SYLLABUS/COMPONENT: 9702/05
PHYSICS
Paper 5 (Practical (A2))
A/AS LEVEL EXAMINATIONS - JUNE 2003970205
3 1(a)(v)Measurements
6 sets of readings (I10) scores 1 mark
Allow more than 6 sets without penalty
Write the number of readings as a ringed total by the table
Choose a row in the table
Check a value for tan . Tick if correct and score 1 mark
If incorrect, write in correct value and do not award the mark
Ignore small rounding errors
All values of < 90° score 1 mark
Minor help from the Supervisor -1. Major help, then -2
If help has been given then write SR at the top of the front page of
the script, and give a brief explanation of the type of help that has
been given by the table of results
1
(a)(v)Repeats
Expect to see at least two sets of readings for , with an average
calculated
Do not award this mark if all the results are the same
2/1/0
(a)(v)Quality of results
Judge by scatter of points about the line of best fit
6 trend points with little scatter scores 2 marks
5 trend points with little scatter scores 1 mark
Shallow curve can score 1 mark
4 trend points only scores zero
Wrong trend or ‘impossible results’ cannot score these marks
1
(a)(v)Column headings
Apply to the current column only
There must be some distinguishing mark between the quantity and
the unit
Allow I/A, I (A) or I in A
(a)(v)Consistency
2/1/0 Apply to both and I
All values of must be given to the same number of d.p.
Allow to be given to the nearest half degree or nearest degree
All values of I must be given to the same number of d.p. (0.1 A or 0.01 A)
Do not accept values to the nearest Ampere or milliampere
2/1/0
(a)(vi)Justification of sf in tan
Answer must relate the number of sf in to the number of sf in tan
Do not allow answers in terms of decimal places
‘Raw data’ ideas can score 1 mark
1
(b)(i)Axes
The axes must be labelled with the quantities plotted
Ignore units on the axes
The plotted points must occupy at least half the graph grid in both
the x and y directions (i.e. 4 large squares in the x-direction and 6
large squares in the y-direction)
Do not allow more than 3 large squares between the labels on an axis
Do not allow awkward scales (e.g. 3:10, 6:10, etc.)
A/AS LEVEL EXAMINATIONS - JUNE 2003970205
1 (b)(i)Plotting of points
All the observations must be plotted
Count the number of plots and ring this total on the grid
Do not allow plots in the margin area
Check one suspect plot. Circle this plot. Tick if correct. If incorrect,
mark the correct position with a small cross and use an arrow to
indicate where the plot should have been, and -1. Allow errors up to
and including half a small square
1 (b)(i)Line of best fit
Only a drawn straight line through a linear trend is allowable for this
mark
This mark can only be awarded for 5 or more plots on the grid
There must be a reasonable balance of points about the drawn line
Do not allow a line of thickness greater than half a small square
1 (b)(ii)Gradient
Ignore any units given with the value
Hypotenuse of ? must be > half the length of line drawn
Check the read-offs. Work to half a small square. ?x/?y gets zero
Values taken from the table that lie on the line to within half a small
square are acceptable
Do not award this mark if a curve has been drawn
(c)k = candidate’s gradient1
(c)Unit of k (i.e. A-1)1
(c)SF in k
1 Allow
2 or
3 sf only
1 (d)(i)Value of when I = 15 A
Method of working must be checked. Ignore unit and small rounding
errors
1 (d)(ii)Reasons for not being able to verify experimentally
Heating problems with the wires
Fuse may blow on psu/max. output current on psu exceeded
Do not allow vague answers such as ‘It is dangerous’
20 marks in total
A/AS LEVEL EXAMINATIONS - JUNE 2003970205
1 2A1Sensible choice of equipment and procedure OK
(i.e. measure count rate and p.d.; change p.d. and measure new
count rate)
Unworkable methods/inappropriate choice of apparatus cannot score
this mark
A2Voltmeter shown in parallel with the GM tube or the supply1
A3Ratemeter/scalar/datalogger connected to terminals A and B of GM
1 tube
B1Radium or Cobalt source used1
B2Reason for choice
1 Answer must relate to half-life. This mark cannot be scored if B1= 0
B3Method of removing a or b radiation (depending on source used)
1 Appropriate absorber is expected. Accept ‘aluminium’ or thin lead
Could be shown on the diagram. Allow electric or magnetic deflection
2 C1/2Any two safety precautions
https://www.sodocs.net/doc/887339489.html,e source handling tool
store source in lead lined box when not in use
do not point source at people/do not look directly at source
Do not allow ‘protective clothing’, ‘lead suits’, ‘lead gloves’, ‘goggles’,
etc.
D1/2Any good/further detail
2 Examples of creditworthy points might be:
Repeat readings (to allow for randomness of activity) or scalar + long
time
Sensible value of p.d. applied to GM tube (i.e. 50 V to 1000 V)
Keep distance from source to GM tube constant/fixed/same, etc.
Subtract count rate due to background radiation
Aluminium sheets must be mm or cm thickness
Allow other valid points. Any two, one mark each
10 marks in total
June 2003
GCE ADVANCED SUBSIDIARY LEVEL AND ADVANCED LEVEL
MARK SCHEME
MAXIMUM MARK: 40
SYLLABUS/COMPONENT: 9702/06
PHYSICS
Paper 6 (Options (A2))
Categorisation of marks
The marking scheme categorises marks on the MACB scheme.
B marks: These are awarded as independent marks, which do not depend on other marks. For a B-mark to be scored, the point to which it refers must be seen specifically in the candidate’s answer.
M marks: These are method marks upon which A-marks (accuracy marks) later depend. For an
M-mark to be scored, the point to which it refers must be seen in the candidate’s answer. If a candidate fails to score a particular M-mark, then none of the dependent A-marks can be scored.
C marks: These are compensatory method marks which can be scored even if the points to which they refer are not written down by the candidate, providing subsequent working gives evidence that they must have known it. For example, if an equation carries a C-mark and the candidate does not write down the actual equation but does correct working which shows he/she knew the equation, then the C-mark is awarded.
A marks: These are accuracy or answer marks which either depend on an M-mark, or allow a C-mark to be scored.
Conventions within the marking scheme
BRACKETS
Where brackets are shown in the marking scheme, the candidate is not required to give the bracketed information in order to earn the available marks.
UNDERLINING
In the marking scheme, underlining indicates information that is essential for marks to be awarded.