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期末复习一1

期末复习一1
期末复习一1

期末复习一

一.选择题

1.(2015?黔南州)下列说法错误的是()

A.﹣2的相反数是2B.3的倒数是C.(﹣3)﹣(﹣5)=2D.﹣11,0,4这三个数中最小的数是0

2.(2015?毕节市)下列说法正确的是()

A.一个数的绝对值一定比0大B.一个数的相反数一定比它本身小

C.绝对值等于它本身的数一定是正数D.最小的正整数是1

3.(2015?六盘水)下列运算结果正确的是()

A.﹣87×(﹣83)=7221 B.﹣2.68﹣7.42=﹣10 C.3.77﹣7.11=﹣4.66 D.

4.(2015?安顺)餐桌边的一蔬一饭,舌尖上的一饮一酌,实属来之不易,舌尖上的浪费让人触目惊心,据统计,中国每年浪费的食物总量折合粮食约500亿千克,这个数据用科学记数法表示为()

A.5×109千克B.50×109千克C.5×1010千克D.0.5×1011千克

5.(2015?无锡)给出下列判断:

①2πa2b与b是同类项;②多项式5a+4b﹣1中,常数项是1;③,+1,都是整式;④几个数相乘,积的符号一定由负因数的个数决定.其中判断正确的是()

A.①②③B.①③ C.①③④D.①②③④

6.(2015?平房区)为了解决老百姓看病难的问题,卫生部门决定大幅度降低药品

的价格,某种常用药品降价40%后的价格为a元,则降价前此药品价格为()

A.元B.元C.40%元D.60%元

7.(2015?绵阳)如图是一个长方形的窗框,其长为a(m),高为b(m),装有同样大的塑钢玻璃,当第②块向右拉到与第③块重叠,再把第①块向右拉到与第②块重叠时,用含a与b的式子表示窗子的通风面积是()m2.

A.B.C.D.

8.(2015?河南模拟)如图所示的运算程序中,若开始输入的

x值为48,我们发现第一次输出的结果为24,第二次输出的

结果为12,…,则第2012次输出的结果为()

A.3 B.6 C.32012 D.62012

二.填空题(共9小题)

9.(2015秋?连云港)某种零件,标明要求是φ20±0.02 mm(φ表示直径,单位:毫米),经检查,一个零件的直径是

19.9 mm,该零件(填“合格”或“不合格”).

10.(2015?松山区)如图,数轴的单位长度为1,如果R表示的数是﹣1,则数轴上表示相反数的两点是.11.(2015?阳谷县)|a﹣b|=b﹣a,且|a|=3,|b|=2,则(a+b)3的值为.

12.(2015?孝义市)观察下列单项式:3a2、5a5、7a10、9a17、11a26…它们是按一定规律排列的,那么这列式子的第n 个单项式是.

13.(2015?路南区)已知P=xy﹣5x+3,Q=x﹣3xy+2,当x≠0时,3P﹣2Q=5恒成立,则y=.14.(2015?开封)多项式﹣2m2+3m﹣的各项系数之积为.

15.(2015?绵阳)当x=1时,px3+qx+6的值为2015,当x=﹣1时,px3+qx+6的值为.

三.解答题(共7小题)

16、已知:(x﹣3)2+|y+2|=0,求代数式2x2+(﹣x2﹣2xy+2y2)﹣2(x2﹣xy+2y2)的值.

17.某自行车厂计划一周生产自行车1400辆,平均每天生产200辆,但由于种种原因,实际每天生产量与计划量相比有出入.下表是某周的生产情况(超产记为正、减产记为负):

星期一二三四五六日

增减+6 ﹣2 ﹣4 +12 ﹣10 +16 ﹣8

(1)根据记录的数据可知该厂星期四生产自行车辆;

(2)根据记录的数据可知该厂本周实际生产自行车辆;

(3)产量最多的一天比产量最少的一天多生产自行车辆;

(4)该厂实行每周计件工资制,每生产一辆车可得30元,若超额完成任务,则超过部分每辆另奖20元;少生产一辆扣15元,那么该厂工人这一周的工资总额是多少元?

18.(2015?巴中)张叔叔在南涧“龙凤丽都”房地产公司买了一套经济适用房,他准备将地面铺上地砖,这套住宅的建筑平面图(由四个长方形组成)如图所示(图中长度单位:米),解答下列问题:

(1)用式子表示这所住宅的总面积.

(2)若铺1平方米地砖平均费用120元,求当x=6时,

这套住宅铺地砖总费用为多少元?

19.(2015?定州市)迪雅服装厂生产一种夹克和T恤,夹克每件定价100元,T恤每件定价50元.厂方在开展促销活动期间,向客户提供两种优惠方案:①买一件夹克送一件T恤;②夹克和T恤都按定价的80%付款.现某客户要到该服装厂购买夹克30件,T恤x件(x>30).

(1)若该客户按方案①购买,夹克需付款元,T恤需付款元(用含x的式子表示);若该客户按方案②购买,夹克需付款元,T恤需付款元(用含x的式子表示);

(2)若x=40,通过计算说明按方案①、方案②哪种方案购买较为合算?

(3)若两种优惠方案可同时使用,当x=40时,你能给出一种更为省钱的购买方案吗?试写出你的购买方案,并说明理由.

20.(2015?吴中区)某市煤气公司按以下规定收取煤气费:每户每月用煤气不超过60立方米,按每立方米0.8元收费:如果每月超过60立方米,超过部分按每立方米1.2元收费.

(1)设甲用户某月用煤气x立方米,用含x的代数式表示甲用户该月所缴的煤气费.若x≤60时,则费用表示为

元;若x>60时,则费用表示为元.

(2)若甲用户10月份缴纳的煤气费是84元,求甲用户10月份用去煤气多少立方米?

21.如图,已知A,B两点在数轴上,点A表示的数为﹣10,OB=3OA,点M以每秒3个单位长度的速度从点A向右运动.点N以每秒2个单位长度的速度从点O向右运动(点M、点N同时出发)

(1)数轴上点B对应的数是.

(2)经过几秒,点M、点N分别到原点O的距离相等?

(3)当点M运动到什么位置时,恰好使AM=2BN?

一.选择题(共12小题)

1.(2015?黔南州)下列说法错误的是(D)

A.﹣2的相反数是2B.3的倒数是C.(﹣3)﹣(﹣5)=2D.﹣11,0,4这三个数中最小的数是0

2.(2015?毕节市)下列说法正确的是(D)

A.一个数的绝对值一定比0大B.一个数的相反数一定比它本身小

C.绝对值等于它本身的数一定是正数D.最小的正整数是1

3.(2015?六盘水)下列运算结果正确的是(A)

A.﹣87×(﹣83)=7221 B.﹣2.68﹣7.42=﹣10C.3.77﹣7.11=﹣4.66 D.

4.(2015?河北)计算:3﹣2×(﹣1)=(A)A.5 B.1 C.﹣1 D.6

5.(2015?安顺)餐桌边的一蔬一饭,舌尖上的一饮一酌,实属来之不易,舌尖上的浪费让人触目惊心,据统计,中国每年浪费的食物总量折合粮食约500亿千克,这个数据用科学记数法表示为(C)

A.5×109千克B.50×109千克C.5×1010千克D.0.5×1011千克

6.(2015?河北模拟)已知单项式3x a+1y4与﹣2y b﹣2x3是同类项,则下列单项式,与它们属于同类项的是(A)A.﹣5x b﹣3y4B.3x b y4C.x a y4D.﹣x a y b+1

7.(2015秋?无锡期中)给出下列判断:①2πa2b与b是同类项;②多项式5a+4b﹣1中,常数项是1;③,+1,都是整式;④几个数相乘,积的符号一定由负因数的个数决定.其中判断正确的是(B)

A.①②③B.①③ C.①③④D.①②③④

8.(2015?平房区二模)为了解决老百姓看病难的问题,卫生部门决定大幅度降低药品的价格,某种常用药品降价40%

后的价格为a元,则降价前此药品价格为(B)A.元B.元C.40%元D.60%元9.(2015?绵阳模拟)如图是一个长方形的铝合金窗框,其长为a(m),高为b(m),装有同样大的塑钢玻璃,当第②块向右拉到与第③块重叠,再把第①块向右拉到与第②块重叠时,用含a与b的式子表示这时窗子的通风面积是

()m2.A.B.C.D.

解:[a﹣﹣﹣×(﹣)]×b=ab.故选B.

10.(2015?蓟县一模)二次三项式3x2﹣4x+6的值为9,则的值为(D)A.18 B.12 C.9 D.7

11.(2015?山亭区模拟)当x=1时,代数式ax3﹣3ax+4的值是7,则当x=﹣1时,这个代数式的值是(C)

A.7 B.3 C.1 D.﹣7

12.(2015?河南模拟)如图所示的运算程序中,若开始输入的x值为48,我们发现第一次输出的结果为24,第二次输出的结果为12,…,则第2012次输出的结果为(A)A.3 B.6 C.32012 D.62012

二.填空题(共9小题)

13.(2015秋?连云港期中)某种零件,标明要求是φ20±0.02 mm(φ表示直径,单位:毫米),经检查,一个零件的直径是19.9 mm,该零件不合格(填“合格”或“不合格”).

14.(2015?松山区)如图,数轴的单位长度为1,如果R表示的数是﹣1,则数轴上表示相反数的两点是P,Q.15.(2015?阳谷县二模)|a﹣b|=b﹣a,且|a|=3,|b|=2,则(a+b)3的值为﹣1或﹣125.

16.(2015?孝义市一模)观察下列单项式:3a2、5a5、7a10、9a17、11a26…它们是按一定规律排列的,那么这列式子的第n个单项式是(2n+1)a..

17.(2015?路南区二模)已知P=xy﹣5x+3,Q=x﹣3xy+2,当x≠0时,3P﹣2Q=5恒成立,则y=.18.(2015秋?开封校级月考)多项式﹣2m2+3m﹣的各项系数之积为3.

19.(2015?绵阳模拟)当x=1时,px3+qx+6的值为2015,当x=﹣1时,px3+qx+6的值为﹣2003.

20.(2015?南京二模)如果代数式2x+y的值是3,那么代数式7﹣6x﹣3y的值是﹣2.

21.(2015?廊坊一模)如图是一个运算程序的示意图,若开始输入x的值为81,则第2014次输出的结果为1三.解答题(共7小题)

22.解:原式=﹣2x2﹣y2+x2﹣y2﹣3=﹣x2﹣y2﹣3,

当x=﹣1,y=﹣时,原式=﹣1﹣﹣3=﹣4.

先化简再求值:已知:(x﹣3)2+|y+2|=0,求代数式2x2+(﹣x2﹣2xy+2y2)﹣2(x2﹣xy+2y2)的值.

解:∵(x﹣3)2≥0,|y+2|≥0,

∴x﹣3=0,x=3,y+2=0,y=﹣2,

原式=2x2+﹣x2﹣2xy+2y2﹣2x2+xy﹣2y2=﹣x2﹣2y2=﹣9﹣8=﹣17.

24.解:(1)超产记为正、减产记为负,所以星期四生产自行车200+12辆,故该厂星期四生产自行车212辆;(2)根据题意知,6﹣2﹣4+12﹣10+16﹣8=10,200×7+10=1410辆,故该厂本周实际生产自行车1410辆;

(3)根据图示产量最多的一天是216,产量最少的一天是190,216﹣190=26辆,

故产量最多的一天比产量最少的一天多生产自行车26辆;

(4)根据图示本周工人工资总额=7×200×30+10×50=42500元,

故该厂工人这一周的工资总额是42500元.

25解:(1)总面积=2x+x2+4×3+2×3=x2+2x+18;

(2)x=6时,总面积=62+2×6+18=36+12+18=66m2,

所以,这套住宅铺地砖总费用为:66×120=7920元.

26.解:(1)3000;50(x﹣30);2400;40x;

(2)当x=40,按方案①购买所需费用=30×100+50(40﹣30)=3000+500=3500(元);按方案②购买所需费用

=30×100×80%+50×80%×40=2400+1600=4000(元),

所以按方案①购买较为合算;

(3)先按方案①购买夹克30件,再按方案②购买T恤10件更为省钱.理由如下:

先按方案①购买夹克30件所需费用=3000,按方案②购买T恤10件的费用=50×80%×10=400,

所以总费用为3000+400=3400(元),小于3500元,

所以此种购买方案更为省钱.

27.解:(1)若x≤60时,则费用表示为0.8x元;若x>60时,则费用表示为60×0.8+1.2(x﹣60)=1.2x﹣24元.(2)由题意可知,1.2x﹣24=84,

解得:x=90.

答:甲用户10月份用去煤气90立方米.

28.解:(1)OB=3OA=30.故B对应的数是30;

(2)设经过x秒,点M、点N分别到原点O的距离相等

①点M、点N在点O两侧,则

10﹣3x=2x,解得x=2;

②点M、点N重合,则

3x﹣10=2x,解得x=10.

所以经过2秒或10秒,点M、点N分别到原点O的距离相等;

(3)设经过y秒,恰好使AM=2BN.

①点N在点B左侧,则

3y=2(30﹣2y),解得y=,3×﹣10=;

②点N在点B右侧,则

3y=2(2y﹣30),解得y=60,3×60﹣10=170;

即点M运动到或170位置时,恰好使AM=2BN.故答案为:30.

人教版英语必修四U1Women of achievement第一课时作业

B4U1 Women of achievement第一课时作业 班级__________ 姓名___________ 座位___________ 评分___________ 一、话题词汇、短语默写(每题2分, 满分28分) 1. 运动,战役,作战(n./vi.)____________ 2. 举动,表现(vt./vi.)_______________ 3. 值得的,值得做的(adj.)____________ 4. 联系,纽带(n.)__________________ 5. 组织,机构,团体(n.)_____________ 6. 直言的,坦诚的(adj.)_____________ 7. 娱乐,款待(n.)___________________ 8. 鼓舞,激发(vt.)_________________ 9. 突发事件(n.)_____________________ 10. 成就,功绩(n.)_____________ 11. 一代,一辈(n.)_________________ 12. 离开,启程,出发_________________ 13. 过着···的生活_______________ 14. 碰巧_____________________ 二、根据首字母或中文提示,用单词或短语的恰当形式填空。(注意:1-9题填写单词;10-13填写短语)(每题2分, 满分26分) 1.They a with the waiter about the price of the meal just now. 1. 2.The book i________ for adults is not suitable for teenagers to read. 2. 3.My sister is against my travel plan while my parents s________ me. 3. 4.It was c________ of you to turn down the radio while I was reading. 4. 5.The doctor said that maybe his disease has c________ with the water he drinks. 5._____________ 6.Mrs. Jones was d_________ of twins last night. 6. 7.The youth should show r_________ for the old people. 7. 8. A person of great d________ usually can achieve his goal. 8. 9. He is absent because of his s________. 9. 10. It was foolish of him to ________ (查阅)his notes during that important test, and as a result, he got punished. 10.___________ 11. I (偶然看到)an old photo while tidying up my study,which reminded me of my happy childhood. 11. 12. After months’ practice,they decided to (坚持)in the face of a lot of difficulties till success. 12. 13. Sweet memories (涌上心头)on her. 13. 三、用所给的词的适当形式填空。(每题3分, 满分24分) 1.Any ________ (organize) that received money from the US government had to treat blacks equally. 2. In ________ (consider) of his age, he did it very well. 3.Their ________ (behave) towards me shows that they don't like me. 4.An eye ________ (special) checked her eyes carefully and advised her not to use her eyes too much. 5.Jane spent many years ________ (observe) and recording their daily activities. 6.Now many theme parks are built for ________ (entertain).

数理统计期末复习题1

2009期末复习题 注:这份答案是在2009年最后一晚做出来的,时间比较紧,所以可能有些地方不严谨,有什么错误还请各位多包涵。 处理一个问题有很多合理的办法,这份答案所列出的只不过代表个人的想法,仅供参考。 这份答案算是送大家的新年礼物吧,预祝大家期末考试顺利,一年都有好运 孟帅 1. 设随机变量X 和Y 相互独立,且都服从正态分布N(0,32),而 921,,,X X X 和921,,,Y Y Y 分别是来自总体X 和Y 的样本,则统计量U = 29 22 21 921Y Y Y X X X ++++++ 服从什么分布?为什么? 解:分子分母同除以9得到 服从N (0,1), 服从X 2(9)分布,因此U 服从 t (9)分布(课本92页) 2.某大学来自A,B 两市的新生中分别抽取10名和11名男生调查身 高,测得他们的身高分别为cm x 176=,cm y 172=,样本方差分别为3.1121=S , 1.92 2=S 。不妨设两个城市的男生的身高分别服从正态分布),(2 1σμN 和 ),(22σμN ,求21μμ-的 95%的置信区间,并请在0.05水平下判断两个城 市的男生身高是否相等? 解: 但是 未知,构造111页) 9 1i X ∑9119i i X =∑ 92 1 3 i i Y =()∑ 22 212σ=σ=σ2σ1 2 X Y --μ-μ

。 =10, =11, =11.3, =9.1, =176, =172。代入T 表达式得到 T= 。 T 服从t ( + -2)查附表7得到 =2.093 得到 的置信区间为: (1.088,6.912) 这个区间不包含0,可以直接判定在0.05水平下两城市男生身 高不相等。如果想严谨一点就在进行假设检验: 原假设:两城市男生身高相等;备择:两城市男生身高不等。 检验统计量 ,和 比较。 如果T 大于 ,拒绝原假设,否则接受。 3.随机调查了某校200名沙眼患者,经用某种疗法治疗一定时期后治愈168人,试求总体治愈率的95%置信区间。 解:样本率p=0.84,用大样本正态近似法求解,置信区间为: ( , )(课本115页) S ω1n 2n 21 S 22 S X Y 1n 2 n ()1241.3915 -μ-μ() 12μ-μ()2 19t 0.05X Y -()219t 0.05() 2 19t 0.052 p u α-2 p u α+

(完整word)人教版高中英语必修四语法填空之课文回顾

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赣县中学“543”教学模式“新授课”学案(人教版)高一英语必修四第一单元主备:潘颖合备:黎玲芳肖娉审核:黎玲芳使用时间:2015.4.24 Unit 1 Women of Achievement Period 1 reading A Student of African Wildlife 【学习目标】 1.能读懂文章,了解世界著名女性的生平故事和Jane Goodall所做出的杰出贡献。 2.通过阅读和微课,总结寻找段落主题句的方法,进而培养概括文章主旨的能力。 3.学会借助思维导图,梳理文章结构。 4.能认识到伟大女性对推动历史发展所起的作用。 【重点难点】 1.提高阅读能力。 2.培养阅读策略,尤其是速读和扫读的阅读策略。 【学法指导】 1.能根据学案和微课,利用合适的阅读策略完成读前和读中练习。 2.完成“课前活动”,限时5分钟完成。 3.通过合作学习,完成精细阅读活动,加深对课文的理解。 【预习检测】 I. Read the text and find out the topic sentence in each paragraph before the lesson. Para1:________________________________________________ Para2:________________________________________________ Para3: _______________________________________________ Para4: _______________________________________________ II. Read the text again. Each group is responsible for a paragraph. Based on your paragraph, can you ask some questions? Each student ask one question, and your question and answer should be in the same paragraph. Group leaders collect these questions, choose the best one to hand in before the lesson. Group 1 and 5------paragraph 1 Group 2 and 6------paragraph 2 Group 3------paragraph 3 Group 4 ------paragraph 4 Question:___________________________________________________________________ Answer:____________________________________________________________________ III. Pre-reading: Answer the following two questions: 1.Why do you think Jane Goodall went to Africa to study chimps rather than to a university? ___________________________________________________________________________ 2.Can you think of the possible difficulties that Jane Goodall might meet doing her research without training? ___________________________________________________________________________ 【合作探究】 IV. While-reading:skimming & careful reading&scanning 1. Skimming (1) matching Para1. Jane’s attitude to the animals Para2. A day in the park Para3. Jane’s achievements Para4. Jane’s way to study chimps and her discovery (2) The passage is mainly about how Jane Goodall worked with ________________________and help people _____________and___________ the life of these animals. 2. Careful-reading: read the text for five minutes and answer the questions asked by students. 3. Scanning 1.What did the group do first in the morning? They_______. A. went into the forest slowly B. left the chimp family sleeping in a tree C. observed the family of chimps wake up D. helped people understand the behavior of the chimps

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