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【全国市级联考】河北省石家庄市2017届高三9月摸底考试理数(解析版)

【全国市级联考】河北省石家庄市2017届高三9月摸底考试理数(解析版)
【全国市级联考】河北省石家庄市2017届高三9月摸底考试理数(解析版)

注意事项:

1.本试卷分第Ⅰ卷和第Ⅱ卷(非选择题)两部分。答卷前,考生务必将自己的姓名、准考证号填在答题卡上。

2.回答第Ⅰ卷时,选出每小题答案后,用铅笔把答题卡上对应题题目的答案标号涂黑,如需改动,用橡皮擦擦干净后,再选涂其他答案标号,写在本试卷上无效。

3.回答第Ⅱ卷时,将答案写在答题卡上,写在本试卷上无效。

4.本试卷满分150分,考试时间为120分钟;考试结束后,将本试卷和答题卡一并交回。

第Ⅰ卷 选择题(共60分)

一、选择题(本大题共12个小题,每小题5分,共60分。在每小题给出的四个选项中,只有一项是符合题目要求的。)

1.若集合{}2log 12<x x P ≤=,{

}3,2,1=Q ,则=Q P ? A.{

}2,1 B.{}1 C.{}3,2 D.{}3,2,1 【答案】C

【解析】 试题分析:{}{}21log 2|24P x x x x =≤=≤<<,所以{}2,3P

Q =,故选C. 考点:1.对数函数的性质;2.集合的运算.

2.复数i

i z +-=12在复平面上对应的点位于 A.第一象限 B.第二象限 C.第三象限 D.第四象限

【答案】D

考点:1.复数的运算;2.复数相关的概念.

3.设R a ∈,则“4=a 是“直线038:1=-+y ax l 与直线02:2=-+a ay x l 平行”的

A.充分不必要条件

B.必要不充分条件

C.充要条件

D.既不充分也不必要条件

【答案】A

考点:1.两条直线的位置关系;2.充分条件与必要条件.

4.下列函数中为偶函数又在),0(+∞上是增函数的是

A.x

y )21

(= B.2y x = C.x y ln = D.x y -=2 【答案】B

【解析】

试题分析:由函数的奇偶性定义可知,选项C,D 为非奇非偶函数,排除C 、D ,选项A 中,1

()2x

y =在区间(0,)+∞上是减函数,故选B.

考点:函数的奇偶性与单调性.

5.执行右图的程序框图,如果输入3=a ,那么输出的n 的值为

A.4

B.3

C.2

D.1

【答案】A

【解析】

试题分析:模拟算法:开始:输入3a =,0,1,0p n θ===,p θ≤,是;

0031,2113,011p n θ=+==?+==+=,p θ≤,是;

1134,2317,112p n θ=+==?+==+=,p θ≤,是;

24313,27115,213p n θ=+==?+==+=,p θ≤,是;

313340,215131,314p n θ=+==?+==+=,p θ≤,否,输出4n =; 故选A.

考点:程序框图.

6.将函数)64sin(3π+

=x y 的图像上各点的横坐标伸长为原来的2倍,再向右平移6π个单位,所得函数图像的一个对称中心为

A.)0,487(π

B.)0,3(π

C.)0,85(π

D.)0,12

7(π 【答案】

D

考点:1.函数的伸缩变换与平移变换;2.三角函数的图象与性质.

7.已知y x ,满足约束条件??

???≥+-≤-≤+03045y x y x y x ,则下列目标函数中,在点)1,4(处取得最大值的是

A.y x z -=51

B.y x z +-=3

C.15

z x y =-- D.y x z -=3 【答案】D

【解析】 试题分析:在直角坐标系内作出可行域如下图所示,由线性规划知识可知,目标函数15

z x y =-与3z x y =-+均是在点(5,1)A --处取得最大值,目标函数15z x y =--在点(1,4)C 处取得最大值,目标函

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