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金融时间序列分析英文试题(芝加哥大学) (1)

金融时间序列分析英文试题(芝加哥大学) (1)
金融时间序列分析英文试题(芝加哥大学) (1)

Graduate School of Business,University of Chicago

Business41202,Spring Quarter2008,Mr.Ruey S.Tsay

Solutions to Midterm

Problem A:(30pts)Answer brie?y the following questions.Each question has two points.

1.Describe two methods for choosing a time series model.

Answer:Any two of(a)Information criteria such as AIC or BIC,(b)Out-of-sample forecasts,and(c)ACF and PACF of the series.

2.Describe two applications of volatility in?nance.

Answer:Any two of(a)derivative(option)pricing,(b)risk management,(c)portfolio selection or asset allocation.

3.Give two applications of seasonal time series models in?nance.

Answer:(a)Earnings forecasts and(b)weather-related derivative pricing or risk man-agement.

4.Describe two weaknesses of the ARCH models in modelling stock volatility.

Answer:Any two of(a)symmetric response to past positive and negative shocks,

(b)restrictive,(c)Not adaptive,and(d)provides no explanation about the source of

volatility clustering.

5.Give two empirical characteristics of daily stock returns.

Answer:any two of(a)heavy tails,(b)non-Gaussian distribution,(c)volatility clus-tering.

6.The daily simple returns of Stock A for the last week were0.02,0.01,-0.005,-0.01,and

0.025,respectively.What is the weekly log return of the stock last week?What is the

weekly simple return of the stock last week?Answer:Weekly log return is0.03938;

weekly simple return is0.04017.

7.Suppose the closing price of Stock B for the past three trading days were$100,$120,

and$100,respectively.What is the arithmetic mean of the simple return of the stock for the past three days?What is the geometric average of the simple return of the stock

for the past three days? Answer:Arithmetic mean=1

2

120?100

100

+100?120

120

=0.017.and the geometric mean is

120×100?1=0.

8.Consider the AR(1)model r t=0.02+0.8r t?1+a t,where the shock a t is normally distrib-

uted with mean zero and variance1.What are the variance and lag-1autocorrelation function of r t?

Answer:Var(r t)=1

1?0.82

=2.78and the lag-1ACF is0.8.

1

9.For problems6and7,suppose the daily return r t,in percentages,of Stock A follows

the model r t=1.0+a t+0.3a t?1,where a t=σt t withσ2

t =1.0+0.4a2

t?1

and t being

standard normal.What is the unconditional variance of a t?What is the variance of r t?

Answer:Var(a t)=1

1?0.4=1.67.Var(r t)=(1+0.32)σ2

a

=1.82.

10.Suppose that a n=3.0,what is the1-step ahead forecast for r n+1at the forecast origin

n?What is the1-step ahead volatility forecast of r t at the forecast origin n?

Answer:r n(1)=1+0.3a n=1.9,andσ2

n (1)=1+0.4a2

n

=4.6.

11.Consider the simple AR(1)model r t=100+0.8r t?1+a t,where a t is normally distributed

with mean zero and variance10.Is the r t series mean-reverting?If yes,what is the half-life of the series?

Answer:Yes,r t series is mean-reverting.The half-life is ln(0.5)/ln(0.8)=3.11.

12.Describe two test statistics for testing the ARCH e?ect of an asset return series.Write

down the associated null hypotheses.

Answer:(a)The Ljung-Box statistic Q(m)of the squared shocks,i.e.a2

t .The null

hypothesis is H o:ρ1=ρ2=···=ρm=0,whereρi is the lag-i ACF of a2

t .(b)The

Engle F-test for the regression a2

t =β0+β1a2

t?1

+···+βm a2

t?m

+e t.The null hypothesis

is H o:β1=β2=···=βm=0.

13.Consider the following two IGARCH(1,1)models for percentage log returns:

Model A:σ2

t =1.0+0.1a2

t?1

+0.9σ2

t?1

Model B:σ2

t =0.1a2

t?1

+0.9σ2

t?1

.

Suppose thatσ2

100=20and a100=?2.0.What are the3-step ahead volatility forecasts

for Models A and B?

Answer:For model A:3-step ahead volatility forecast isσ2

100(3)=2+(1.0+0.1×

(?2.0)2+0.9×20)=21.4.For model B,the3-step ahead volatility forecast isσ2

100(3)=

0.1(?2.0)2+0.9×20=18.4.

14.Consider the following two models for the log price of an asset:

Model A:p t=p t?1+a t

Model B:p t=0.00001+p t?1+a t

where the shock a t is normally distributed with mean zero and varianceσ2>0.Suppose further that p100=5.Let p n( )be the -step ahead forecast at the forecast origin n.

What are the point forecasts p100( )for both models as →∞?

Answer:For model A,p100( )=5for all .For model B,p100( )converges to in?nity as →∞.

2

15.Suppose that we have T =1000daily log returns for the Decile 1portfolio.Suppose

further that the sample autocorrelation at lag-12is ?ρ12=0.15.Test the hypothesis H o :ρ12=0against the alternative hypothesis H a :ρ12=https://www.sodocs.net/doc/0e18716902.html,pute the test statistic and draw your conclusion.Answer :t =0.151/√1000=√1000×0.15=4.74,which is highly signi?cant.Thus,the lag-12ACF is not zero.

Problem B .(20pts)It is well-known in economics that growth rate of the domestic gross product (GDP)is negatively correlated with the change in unemployment rate.Consider the U.S.quarterly real GDP and unemployment rate from the ?rst quarter of 1948to the ?rst quarter of 2008.Let dgdp t be the growth rate of the GDP,i.e.dgdp t =ln(GDP t )?ln(GDP t ?1),and dun t be the change in unempolyment rate,i.e.dun t =U t ?U t ?1with U t being the civilian unemployment rate.The data were seasonally adjusted and obtained from the Federal Reserve Bank at St.Louis.The sample size after the di?erencing is https://www.sodocs.net/doc/0e18716902.html,e the attached R output to answer the following questions.

1.(5points)Write down the ?tted linear regression model with dgdp t and dun t representing the dependent and independent variable,respectively,including residual standard error.What is the R 2of the linear regression?Is the ?tted model adequate?Why?

Answer :The ?tted linear regression is

dgdp t =0.017?0.017dun t +e t ,?σe =0.0088.

The R 2is 0.37.The model is not adequate because the Q (m )statistics of the residuals show that the residuals have serial correlations,i.e.Q (12)=219.4with p-value close to zero.

2.(5points)To take care of the serial correlations in the residuals,a linear regression model with time-series errors is built for the two variables.Write down the ?tted model,including the residual variance.

Answer :The ?tted linear regression model with time-series errors is

(1?0.21B ?0.12B 2)(1?0.86B 4)(dgdp t ?0.017+0.018dun t )=(1?0.72B 4)a t ,

?σ2a =6.01×10?5.

3.(2points)Is the model in Question 2adequate?Why?

Answer :Yes,the model is adequate.The Q (m )statistics of the residuals fail to indicate the existence of any serial correlations.We have Q (12)=17.53with p-value 0.13.

4.(4points)Based on the ?tted model in Question 2,is the growth rate of GDP negatively correlated with the change in unempolyment rate?Why?

Answer :Yes,the growth rate of GDP is negatively related to the change in unemploy-ment rate.The estimated coe?cient is ?0.018which is highly signi?cant,because it standard error 0.0014is small,resulting in a large t -ratio.

3

5.(4points)To check the predictive power of the model,it was re-estimated using the?rst

236data points.This re-?tted model is used to produce1-step to4-step ahead forecasts at the forecast origin t=236.The actual value of the GDP growth rates are also given.

Construct the1-step ahead95%interval forecast of the model.Is the actual growth rate in the forecasting interval?

Answer:The95%interval forecast is0.012±1.96×0.0077,i.e.[?0.0031,0.027].The actual value is0.0159,which is in the interval.

Problem C.(16pts)Consider the quarterly earnings per share of the Microsoft stock from the?rst quarter of1992to the?rst quarter of2008.The data were obtained from First Call. To take the log transformation,we add0.5to all data points.The R output is attached. Let x t=ln(y t+0.5)be the transformed earnings,where y t is the actual earnings per share.

1.(5points)Write down the?tted model for x t,including the variance of the residuals.

Answer:The?tted model is

(1?B)r t=(1?0.70B+0.39B2)(1+0.39B4)a t,?σ2

a

=0.0016, where r t=ln(x t+0.5)with x t being the earnings per share.

2.(2points)Is there any signi?cant serial correlation in the residuals of the?tted model?

Why?

Answer:No,the Q(m)statistics of the residuals give Q(12)=9.65with p-value0.65.

3.(4points)Let T=65be the forecast origin,where T is the sample size.Based on the

?tted model,and,for simplicity,use the relationship y t=exp(x t)?0.5,what are the 1-step and2-step ahead forecasts of earnings per share for the Microsoft stock?

Answer:The1-step and2-step earnings forecasts are0.56and0.54,respectively.

4.(2points)Test the null hypothesis H o:θ4=0vs H a:θ4=0.What is the test statistic?

Draw your conclusion.

Answer:The test statistic is t=0.3912

0.1442=2.71with two-sided p-value0.0067.Thus,

the seasonal MA coe?cientθ4is signi?cantly di?erent from zero.

5.(3points)Consider the regular(i.e.,non-seasonal)part of the MA model.Is it invertible?

Why?

Answer:Yes,it is invertible,because the polynomial1?0.6953x+0.3889x2has roots

0.89±1.33i so that the absolute value of the roots(Mod in R)is1.6,which is greater

than1.[If you compute the roots of x2?0.6953x+0.3889,the the absolute value of the roots is less than1.]

Problem D.(34pts)Consider the daily log returns of the Starbucks stock,in percentages, from January1993to December2007.The relevant R output is attached.Answer the following questions.

4

1.(2points)Is the mean log return signi?cant di?erent from zero?Why?

Answer:No,the basic statistics show the95%con?dence interval of the mean is [?0.0103,0.1624],which contains zero.

2.(2points)Is there any serial correlation in the log return series?Why?

Answer:Yes,the Q(m)statistics show Q(15)=38.39with p-value0.0008.

3.(2points)An MA model is used to handle the mean equation,which appears to be

adequate.Is there any ARCH e?ect in the return series?Why?

Answer:Yes,because the Q(m)statistics of the squared residuals show Q(15)=112.61 with p-value close to zero.

4.(6points)A GARCH(1,1)model with Student-t distribution is used for the volatility

equation.Write down the?tted model,including the degrees of freedom of the Student-t innovations and mean equation.

Answer:The?tted model is

r t=0.037+a t?0.043a t?1?0.048a t?2,a t=σt t, ~t5.27.

σ2 t =0.012+0.026a2

t?1

+0.973σ2

t?1

.

5.(4points)Since the constant term of the GARCH(1,1)model is not signi?cantly di?erent

from zero at the1%level,an IGARCH(1,1)model is used.Write down the?tted IGARCH(1,1)model,including the mean equation.

Answer:The?tted IGARCH(1,1)model is

r t=0.077+a t?0.029a t?1?0.044a t?2,a t=σt t, t~N(0,1).

σ2 t =0.022a2

t?1

+0.978σ2

t?1

.

6.(3points)Is the IGARCH(1,1)model adequate?Why?What is the3-step ahead

volatility forecast with the last data point as the forecast origin?

Answer:Yes,the Q(m)statistics for the standardized residuals give Q(10)=1.77, Q(15)=10.79,and Q(20)=18.66.The p-values of these statistics are all greater than

0.05.In addition,the Q(m)statistics of the squared standardized residuals also have

large p-values.

The3-step ahead volatility forecast is √

3.779=1.9

4.

7.(5points)A GJR(or TGARCH)model with Student-t distribution is also?tted to the

log return series.Write down the?tted model,including the mean equation and all parameters.

Answer:Thw?tted GJR model is

r t=0.032+a t?0.043a t?1?0.048a t?2,a t=σt t, t~t5.31.

σ2 t =0.015+(0.021+0.017N t?1)a2

t?1

+0.970σ2

t?1

,

where N t?1=0if a t?1≥0and=1,otherwise.

5

8.(2points)Is the ?tted GJR (or TGARCH)model adequate?Why?

Answer :Yes,the Q (m )statistics of the standardized residuals and those of the squred standardized residuals all have large p-values.

9.(2points)Among the GARCH(1,1),IGARCH(1,1)and GJR(1,1)models,which one is preferred?Why?

Answer :The GJR(1,1)model because it has the smallest AIC value.

10.(2points)Is the leverage e?ect of the GJR model signi?cant?Why?

Answer :Yes,the t -ratio of the leverage parameter is 2.01,which is signi?cant at the 5%level.

11.(4points)To better understand the leverage e?ect,use the ?tted GJR to calculate the

ratio σ2t (a t ?1=?5.10)σ2t

(a t ?1=5.10),assuming σ2t ?1=7.5.Answer :

σ2t (a t ?1=?5.10)σ2t (a t ?1=5.10)=0.0154+0.0379×(?5.10)2+0.97×7.50.0154+0.0208×(5.10)2+0.97×7.5

=1.057.

6

最新时间序列分析期末考试B

精品文档 浙江农林大学 2009 - 2010 学年第 二 学期考试卷(A 卷) 课程名称: 应用时间序列分析 课程类别: 必修 考试方式: 闭卷 注意事项:1、本试卷满分100分。 2、考试时间 120分钟。 一、单项选择题(在每小题的四个备选答案中,选出一个正确 答案,并将正确答案的选项填在题后的括号内。每小题2分,共12分) 1. 关于严平稳与(宽)平稳的关系,不正确的为 。 ( ) A. 严平稳序列一定是宽平稳序列 B. 当序列服从正态分布时,两种平稳性等价 C. 二阶矩存在的严平稳序列一定为宽平稳的 D. MA(p)模型一定是宽平稳的 2. 下图为某时间序列的相关检验图,图1为自相关函数图,图2为偏自相关函数图,请选择模型 。 ( ) 图1 图2 学院: 专业班级: 姓名: 学号: 装 订 线 内 不 要 答 题

A. AR(1) B. AR(2) C. MA(1) D. MA(2) 3. 下图中,图3为某序列一阶差分后的自相关函数图,图4为某序列一阶差分后的 偏自相关函数图,请对原序列选择模型。( ) 图3 图4

A.ARIMA(4,1,0) B. ARIMA(0,2,1) C. ARIMA(0,1,2) D.ARI MA(0,1,4) 4. 记B 为延迟算子,则下列不正确的是 。 ( ) A. 0 1B = B. (1)k t t k t X X B X --=- C. 12t t BX X --= D. 11()t t t t B X Y X Y --±=± 5.对于平稳时间序列,下列错误的是 ( ) A.)(212εσεE = B.),(),(k t t k t t y y Cov y y Cov -+= C.k k -=ρρ D.)(?)1(?1k y k y t t +=+ 6.下图为对某时间序列的拟合模型进行显著性水平0.05α=的显著性检验,请选择 该序列的拟合模型 。 ( )

国际金融试题单选

1 办理结汇、售汇的外汇资金划转应符合()外汇管理规定。答案: A ;A 国家B人民银行 C 中国银行 D 农业银行 2 对于无法解付的外汇汇入款项,应在()做暂收处理,并按照我行外汇资金清算查询查复的有关规定进行查询,做好查询查复登记。答案: A ;A 当日B次日C二日内 D 三日内 3 个人客户的外汇汇款,款项到达后,对于提供电话和地址的汇款指示,应首先以()通知收款人。答案: D ; A 信件B邮递C传真D电话 4 个人客户的外汇汇款,款项到达后,以邮递方式通知收款人的,应在()个工作日内发出通知邮件。答案: B ; A 1 B 2 C 3 D 5 5 机构客户申请办理外币票据托收业务的,需核对其票据背书签章和《外币票据托收申请书》上的签章,是否与其在我行的()相符。答案: D ;A 预留公章 B 预留财务章 C 预留法人章 D 预留印鉴 6 机构客户外汇汇款以及账号齐全的个人外汇汇款应在收到上级行下划账单的()个工作日内到达客户账。答案: A ;A 1 B 2 C 3 D 5 7 解付外汇汇入汇款,必须区分机构客户和个人客户,严格按照()的有关规定为客户办理相关手续。答案: D ; A 总行B分行C人民银行 D 国家外汇管理部门 8 经办行办理付汇业务,应按照()的有关规定,办理国际收支统计申报。答案: D ;A 总行B分行C 人民银行 D 国家外汇管理部门 9 经办行要严格按照总行规定的业务办理时间进行结售汇交易,对于当日交易并起息记账的业务,截止时间为当日下午()。答案: D ;A 15:00 B 15:30 C 16:00 D 16:30 10 经办行在办理外汇票汇业务时,可以指示账户行主动借记总行账户,但必须在签发汇票的()以SWIFT MT299报文通知总行外汇清算中心。答案: D ;A 次日下午四点前 B 次日下午三点前 C 当天下午四点前 D 当天 下午三点前 11 申请人办理外币票据托收,应填写《外币票据托收申请书》,一式()联,并签章确认。答案: C ;A 一B 二 C 三 D 四 12 收到无法解付的外汇汇入汇款并向汇款行、账户行发出查询的()个工作日后,无任何实质性答复,仍无法解付的,应做退汇处理。答案: B ;A 10 B 15 C 20 D 30 13 外币票据是重要(),如当日受理的外币票据不能及时寄送代收行,必须妥善保管。答案: B ;A 单据B 有价单证 C 一般凭证 D 空白凭证 14 外币票据托收业务档案应保存()年。答案: B ;A 3 B 5 C 15 D 永久 15 外币票据托收中,()方式适用的票据范围最广。答案: C ;A 立即贷记 B 最终贷记 C 标准托收 D 特殊托收 16 外币票据托收中,代收行应选择与我行签有()的代理行进行办理。答案: D ;A 托收业务协议 B 票据 托收业务协议 C 代理托收业务协议D 代理票据托收业务协议 17 外币票据托收中,对于凭保付款托收回来的票据款项,应要求申请人在我行至少存足()个月方可使用. 答案: A ;A 1 B 2 C 3 D 6 18 外币票据托收中,经办行收票后,应在每张托收票据的()加盖划线章,划线分普通划线和特别划线。答案: A ;A 正面左上角 B 正面右上角 C 反面左上角 D 反面右上角 19 外币票据托收中,经办行要严格审查票据背书的真实性和完整性,对金额较大或有疑问的票据我行可采用()方式。 答案: A ;A 标准托收 B 立即贷记 C 最终贷记 D 以上三种都可以 20 外币票据托收中,票面的收款人可能以中文、英文(按拼音核对)或中英文对照之中的一种形式进行表示,如果用中英文同时表示,应以()为准。答案: A ;A 中文B英文C中、英文一起 D 中、英文均可 21 外币票据托收中,如果票据无特别注明,大多数票据自出票日期起()个月内有效(如美元支票、英镑支票等),超过有效期的票据我行不予受理。答案: D ;A 1 B 2 C 3 D 6 22 外币票据托收中,无论采用何种托收方式,我行对托收票据发生的退票均保留随时向()追索的权利。答案:C ;A 收款人 B 付款人 C 申请人 D 出票人 23 外币票据托收中,一般票据都注明了完整的货币符号,但有些票据的货币符号不完整,经办行应根据票据注明的()来确定票据的币种。答案: A ;A 付款地 B 收款地 C 收款人 D 付款人 24 外币票据托收中,因退票发生的费用,由()承担。答案: D ;A 收款人 B 付款人 C 出票人D 申请人 25 外汇汇出汇款和汇入汇款的查询查复业务,应执行()外汇资金清算查询查复的有关规定答案: C ;A 外汇 局 B 银监局 C 总行D分行

时间序列分析在金融市场价格波动分析中应用

时间序列分析在金融市场价格波动分析中应用

B 题 金融市场价格波动分析 摘要 本文基于),,(q d p ARIMA 模型以及GARCH 模型结合数据图法,自相关函数检验法,差分法,借助SAS 软件和views E 软件建立数学模型,针对金融市场特性与走势并检验金融指数序列的平稳性及波动性,分析不同金融市场的风险并进行拟合与预测,并对不同金融市场的波动溢出等问题进行了检验与分析,最后给出了结论。 对于问题一,我们直接运用数据图法对纽约道琼斯指数进行分析。通过运 用SAS 软件编程得到2012年纽约道琼斯连续两百天的收盘指数时序图,得出道琼斯指数呈现循环上升下降的特性,总体呈现上升的走势。 对于问题二,我们运用GARCH 模型与自相关函数检验法对道琼斯指数进行指数序列的波动性及平稳性检验。通过建立GARCH 模型并结合views E 给出了波动性检验表,最后得出了过去的波动对未来的影响是逐渐减小的结论。运用自相关函数检验法,用SAS 程序得出道琼斯指数序列的自相关图,通过对自相关图的分析,我们得出金融时间序列存在一定的非平稳性。 对于问题三,我们运用差分法对道琼斯价格指数进行平稳化处理和白噪声 检验。我们先对先对时间序列进行一阶差分运算,然后用SAS 画出时序图,判断出经过一阶差分后的时间序列为平稳的,并且用自相关函数检验法进行检验再次验证了一阶差分后的时间序列为平稳的,即完成了平稳化处理。 对于问题四,我们建立),,(q d p ARIMA 模型通过SAS 程序对道琼斯价格指数与上证指数进行拟合,然后进行了模型的适应性检验、参数的显著性检验和残

差的白噪声检验并且都通过了,最后对两个股市指数进行了未来五个时刻的预测并且给出了区域,预测效果比较好。 对于问题五,我们运用GARCH模型通过views E对道琼斯股市和上证股市两个市场的波动是否存在波动溢出进行了分析。通过对提取的条件方差GARCH01和GARCH02进行ranger G因果检验最后得出了两个股票市场不存在明显的溢出效应的结论。 关键词:金融指数自相关函数检验差分法) p d ARIMA模型SAS (q , , G因果检验 views E GARCH模型ranger 一.问题重述 2008年全球金融危机昭示了金融市场价格波动的严重后果。金融时间序列收益率序列的波动是动态变化的,是不可知,或可知但不可测。不同金融市场的波动还存在波动溢出。 请收集不同金融市场的指标数据(如上海、深圳、新加坡、纽约等地的股市指数)进行如下建模与分析: 1、单个分析金融市场的特性与走势 2、分析与检验金融指数序列的平稳性及波动性 3、根据价格波动性,进行平稳化处理 4、分析每个市场的风险,并进行拟合和预测 5、请讨论多个不同金融市场之间的波动溢出问题 二.问题分析

金融时间序列分析_期中试卷

一.名词解释(每小题5分,共20分) 1. 零均值白噪声序列 2. 严平稳序列 3. 自协方差函数 4. 均方意义下收敛

二.简答题(每小题10分,共20分) 1.请简述ARMA(p,q)序列的之平稳域的定义。 2.请简要描述Ljung-Box检验的过程(包括原假设、备择假设、统计 量的定义和抽样分布)

三.计算分析题(每小题15分,共45分) 1. 设cos()sin()t t t X ξη+=,其中ξ,η独立且服从N(0,1)。 完成下列问题: 1a : 给出{}t X 的自协方差函数(,)t t k γ+和自相关函数(,)t t k ρ+的表达 式;(10分) 1b :{}t X 是二阶宽平稳序列吗,为什么?(5分)

2.考虑时间序列 120.25t t t t X X X ε--=+- 其中t ε为一零均值白噪声序列,方差为2。 2a: 判断该序列的种类,并说明该序列是否是二阶宽平稳序列(5分); 2b : 给出该序列的自协方差函数(10分)。

3. 判定下列各序列的阶数,然后判断平稳性(给出详细的理由和判断 步骤) 3a. 12100.30.20.3t t t t t X X X εε----+=-(5分) 3b. 21.2t t t X εε-=-(5分) 3c. 1t t t X X ε--=(5分)

四.证明题(15分) 若序列0t k k k t X c ε∞-==∑,其中{},0,1,2,...t t ε=是零均值白噪声序列,方差 为2τ,02k k c =∞∞<∑。试证明: 1. 0t EX = (5分); 2. ()20cov ,t s j s t j j X X c c σ∞ -+==∑ (10分)。

应用时间序列分析试卷一

应用时间序列分析试卷 一 Document number【980KGB-6898YT-769T8CB-246UT-18GG08】

应用时间序列分析(试卷一) 一、 填空题 1、拿到一个观察值序列之后,首先要对它的平稳性和纯随机性进行检验,这两个重要的检验称为序列的预处理。 2、白噪声序列具有性质纯随机性和方差齐性。 3、平稳AR (p )模型的自相关系数有两个显着的性质:一是拖尾性;二是呈负指数衰减。 4、MA(q)模型的可逆条件是:MA(q)模型的特征根都在单位圆内,等价条件是移动平滑系数多项式的根都在单位圆外。 5、AR (1)模型的平稳域是{}11<<-φφ。AR (2)模型的平稳域是 {}11,12221<±<φφφφφ且, 二、单项选择题 1、频域分析方法与时域分析方法相比(D ) A 前者要求较强的数学基础,分析结果比较抽象,不易于进行直观解释。 B 后者要求较强的数学基础,分析结果比较抽象,不易于进行直观解释。 C 前者理论基础扎实,操作步骤规范,分析结果易于解释。 D 后者理论基础扎实,操作步骤规范,分析结果易于解释。 2、下列对于严平稳与宽平稳描述正确的是(D ) A 宽平稳一定不是严平稳。 B 严平稳一定是宽平稳。 C 严平稳与宽平稳可能等价。 D 对于正态随机序列,严平稳一定是宽平稳。 3、纯随机序列的说法,错误的是(B )

A时间序列经过预处理被识别为纯随机序列。 B纯随机序列的均值为零,方差为定值。 C在统计量的Q检验中,只要Q 时,认为该序列为纯随机序列,其 中m为延迟期数。 D不同的时间序列平稳性检验,其延迟期数要求也不同。 4、关于自相关系数的性质,下列不正确的是(D) A. 规范性; B. 对称性; C. 非负定性; D. 唯一性。 5、对矩估计的评价,不正确的是(A) A. 估计精度好; B. 估计思想简单直观; C. 不需要假设总体分布; D. 计算量小(低阶模型场合)。 6、关于ARMA模型,错误的是(C) A ARMA模型的自相关系数偏相关系数都具有截尾性。 B ARMA模型是一个可逆的模型 C 一个自相关系数对应一个唯一可逆的MA模型。 D AR模型和MA模型都需要进行平稳性检验。 7、MA(q)模型序列的预测方差为下列哪项(B) A、 []2 2 , Va() , l t l q r e l l q ξ ξ θθσ θθσ ?< ? =? > ?? 22 1-1 22 1q (1++...+) (1++...+) B、 []2 2 , Va() , l t l q r e l l q ξ ξ θθσ θθσ ?≤ ? =? > ?? 22 1-1 22 1q (1++?+) (1++?+) C、 []2 q 2 , Va() , t l l q r e l l q ξ ξ θθσ θθσ ?≤ ? =? > ?? 22 1-1 22 1 (1++?+) (1++?+) D、 []2 2 , Va() , l t l q r e l l q ξ ξ θθσ θθσ ?≤ ? =? > ?? 22 1-1 22 1q-1 (1++?+) (1++?+)

《国际金融实务》题库含答案

第一章外汇交易的一般原理 一、单项选择题: 1、目前,多数国家(包括我国人民币)采用的汇率标价法是( A )。 A、直接标价法 B、间接标价法C应收标价法D、美元标价法 2 、按银行汇款方式不同,作为基础的汇率是(A )。 A、电汇汇率 B、信汇汇率C票汇汇率D、现钞汇率 3、外汇成交后,在未来约定的某一天进行交割所采用的汇率是( B )。 A、浮动汇率 B、远期汇率C市场汇率D、买入汇率 4、若要将出口商品的人民币报价折算为外币报价,应用( A )。 A、买入价 B、卖出价 C、现钞买入价 D、现钞卖出价 5、银行对于现汇的卖出价一般(A )现钞的买入价。 A、高于 B、等于C低于D不能确定 6、我国银行公布的人民币基准汇率是前一日美元对人民币的( B )。 A、收盘价 B、银行买入价 C、银行卖出价D加权平均价 7、外汇规避风险的方法很多。关于选择货币法,说法错误..的是(A )。 A、收“软”币付“硬”币 B 、尽量选择本币计价 C、尽量选择可自由兑换货币 D、软硬币货币搭配 8、下列外汇市场的参与者不包.括..(C )。 A、中国银行 B、索罗斯基金C无涉外业务的国内公司D、国家外汇管理局宁波市分局 9、对于经营外汇实务的银行来说,贱买贵卖是其经营原则,买卖之间的差额一般

为1%。?5%。,是银行经营经营外汇实务的利润。那么下列哪些因素使得买卖差价的幅度越小( A ) A、外汇市场越稳定 B、交易额越小 C、越不常用的货币D外汇市场位置相对于货币发行国越远 10、被公认为全球一天外汇交易开始的外汇市场的( C )。 A、纽约 B、东京 C、惠灵顿 D、伦敦 11、下列不.属.于.外汇市场的参与者有(D )。 A、中国银行 B、索罗斯基金 C、国家外汇管理局浙江省分局 D、无涉外业 务的国内公司 12、在有形市场中,规模最大外汇交易市场的是( A )。 A、伦敦 B、纽约 C、新加坡 D、法兰克福 13 、外汇市场上,银行的报价均以各种货币对( D )的汇率为基础。 A、直接标价法 B、间接标价法C应收标价法D、美元标价法 14、银行间外汇交易额通常以(A )的整数倍。 A、100万美元 B、50万美元 C、1000万美元D 10万美元 15、以点数表示的远期汇率差价,每点所代表每个标准货币所折合货币单位的(A ) A、1/10000 B 、1/10 C 、1/100 D 、1/1000 16、商业银行经营外汇业务时,如果卖出多于买进,则称为( B ) A、多头 B、空头 C、升水 D、贴水 1 7 、下列货币名称与英文简写对应错误..的(B ) A、欧兀一EURO B 澳兀一CAD C、新加坡兀一SGD D 日兀一YEN 18、在伦敦外汇市场上用美元购买日元这样一笔外汇,结算国是( A )。 A美国和日本,交易国是英国B、美国和日本,交易国是美国 C美国和日本,交易国是日本D、美国和日本,交易国是美国和日本 19、一般来讲,一国的国际收支顺差会使其( B )。 A、本币升值 B、物价上升 C、通货紧缩 D、货币疲软 20、以下是两银行交易的过程,根据其交易过程,下列答案错误..的(C )。 A 银行:Hi! Bank of China, Shanghai Branch calling, spot CHF for 6 USD

金融时间序列分析英文试题(芝加哥大学) (1)

Graduate School of Business,University of Chicago Business41202,Spring Quarter2008,Mr.Ruey S.Tsay Solutions to Midterm Problem A:(30pts)Answer brie?y the following questions.Each question has two points. 1.Describe two methods for choosing a time series model. Answer:Any two of(a)Information criteria such as AIC or BIC,(b)Out-of-sample forecasts,and(c)ACF and PACF of the series. 2.Describe two applications of volatility in?nance. Answer:Any two of(a)derivative(option)pricing,(b)risk management,(c)portfolio selection or asset allocation. 3.Give two applications of seasonal time series models in?nance. Answer:(a)Earnings forecasts and(b)weather-related derivative pricing or risk man-agement. 4.Describe two weaknesses of the ARCH models in modelling stock volatility. Answer:Any two of(a)symmetric response to past positive and negative shocks, (b)restrictive,(c)Not adaptive,and(d)provides no explanation about the source of volatility clustering. 5.Give two empirical characteristics of daily stock returns. Answer:any two of(a)heavy tails,(b)non-Gaussian distribution,(c)volatility clus-tering. 6.The daily simple returns of Stock A for the last week were0.02,0.01,-0.005,-0.01,and 0.025,respectively.What is the weekly log return of the stock last week?What is the weekly simple return of the stock last week?Answer:Weekly log return is0.03938; weekly simple return is0.04017. 7.Suppose the closing price of Stock B for the past three trading days were$100,$120, and$100,respectively.What is the arithmetic mean of the simple return of the stock for the past three days?What is the geometric average of the simple return of the stock for the past three days? Answer:Arithmetic mean=1 2 120?100 100 +100?120 120 =0.017.and the geometric mean is 120×100?1=0. 8.Consider the AR(1)model r t=0.02+0.8r t?1+a t,where the shock a t is normally distrib- uted with mean zero and variance1.What are the variance and lag-1autocorrelation function of r t? Answer:Var(r t)=1 1?0.82 =2.78and the lag-1ACF is0.8. 1

英文版国际金融试题和答案

PartⅠ.Decide whether each of the following statements is true or false (10%)每题1分,答错不扣分1. If perfect markets existed, resources would be more mobile and could therefore be transferred to those countries more willing to pay a high price for them. ( T ) 2. The forward contract can hedge future receivables or payables in foreign currencies to insulate the firm against exchange rate risk. ( T ) 3. The primary objective of the multinational corporation is still the same primary objective of any firm, i.e., to maximize shareholder wealth. ( T ) 4. A low inflation rate tends to increase imports and decrease exports, thereby decreasing the current account deficit, other things equal. ( F ) 5. A capital account deficit reflects a net sale of the home currency in exchange for other currencies. This places upward pressure on that home currency’s value. ( F ) 6. The theory of comparative advantage implies that countries should specialize in production, thereby relying on other countries for some products. ( T ) 7. Covered interest arbitrage is plausible when the forward premium reflect the interest rate differential between two countries specified by the interest rate parity formula.( F ) 8.The total impact of transaction exposure is on the overall value of the firm. ( F ) 9. A put option is an option to sell-by the buyer of the option-a stated number of units of the underlying instrument at a specified price per unit during a specified period. ( T ) 10. Futures must be marked-to-market. Options are not. ( T ) PartⅡ:Cloze (20%)每题2分,答错不扣分 1. If inflation in a foreign country differs from inflation in the home country, the exchange rate will adjust to maintain equal( purchasing power ) 2. Speculators who expect a currency to ( appreciate ) could purchase currency futures contracts for that currency. 3. Covered interest arbitrage involves the short-term investment in a foreign currency that is covered by a ( forward contract ) to sell that currency when the investment matures. 4. (Appreciation/ Revalue )of RMB reduces inflows since the foreign demand for our goods is reduced and foreign competition is increased. 5. ( PPP ) suggests a relationship between the inflation differential of two countries and the percentage change in the spot exchange rate over time. 6. IFE is based on nominal interest rate ( differentials ), which are influenced by expected inflation. 7. Transaction exposure is a subset of economic exposure. Economic exposure includes any form by which the firm’s ( value ) will be affected. 8. The option writer is obligated to buy the underlying commodity at a stated price if a ( put option ) is exercised 9. There are three types of long-term international bonds. They are Global bonds , ( eurobonds ) and ( foreign bonds ). 10. Any good secondary market for finance instruments must have an efficient clearing system. Most Eurobonds are cleared through either ( Euroclear ) or Cedel. PartⅢ:Questions and Calculations (60%)过程正确结果计算错误扣2分 1. Assume the following information: A Bank B Bank Bid price of Canadian dollar $0.802 $0.796 Ask price of Canadian dollar $0.808 $0.800 Given this information, is locational arbitrage possible?If so, explain the steps involved in locational arbitrage, and compute the profit from this arbitrage if you had $1,000,000 to use. (5%) ANSWER: Yes!One could purchase New Zealand dollars at Y Bank for $.80 and sell them to X Bank for $.802.With $1 million available, 1.25 million New Zealand dollars could be purchased at Y Bank.These New Zealand dollars could then be sold to X Bank for $1,002,500, thereby generating a profit of $2,500. 2. Assume that the spot exchange rate of the British pound is $1.90.How will this spot rate adjust in two years if the United Kingdom experiences an inflation rate of 7 percent per year while the United

金融时间序列分析

《金融时间序列分析》讲义 主讲教师:徐占东 登录:https://www.sodocs.net/doc/0e18716902.html,徐占东《金融时间序列模型》 参考教材: 1.《金融时间序列的经济计量学模型》经济科学出版社米尔斯著2.《经济计量学手册》章节 3.《Introductory Econometrics for Finance》 Chris Brooks 剑桥大学出版社 4.《金融计量学:资产定价实证分析》周国富著北京大学出版社5.《金融市场的经济计量学》 Andrew lo等上海财经大学出版社6.《动态经济计量学》 Hendry著上海人民出版社 7.《商业和经济预测中的时间序列模型》中国人民大学出版社弗朗西斯著 8.《No Linear Econometric Modeling in Time series Analysis》剑桥大学出版社 9.《时间序列分析》汉密尔顿中国社会科学出版社10.《高等时间序列经济计量学》陆懋祖上海人民出版社11.《计量经济分析》张晓峒经济科学出版社 12.《经济周期的波动与预测方法》董文泉高铁梅著吉林大学出版社 13.《宏观计量的若干前言理论与应用》王少平著南开大学出版社14.《协整理论与波动模型——金融时间序列分析与应用》张世英、樊智著清华大学出版社 15.《协整理论与应用》马薇著南开大学出版社 16.(NBER working paper)https://www.sodocs.net/doc/0e18716902.html,

17.(Journal of Finance)https://www.sodocs.net/doc/0e18716902.html, 18.(中国金融学术研究网) https://www.sodocs.net/doc/0e18716902.html, 教学目的: 1)能够掌握时间序列分析的基本方法; 2)能够应用时间序列方法解决问题。 教学安排 1单变量线性随机模型:ARMA ; ARIMA; 单位根检验。 2单变量非线性随机模型:ARCH,GARCH系列模型。 3谱分析方法。 4混沌模型。 5多变量经济计量分析:V AR模型,协整过程;误差修正模型。

时间序列期末试题B卷

成都信息工程学院考试试卷 2012——2013学年第2学期 课程名称:《金融时间序列分析》 班级:金保111本01、02、03班 一、判断题(每题1分,正确的在括号内打√,错误的在括号内打×,共15分) 1.模型检验即是平稳性检验( )。 2.模型方程的检验实质就是残差序列检验( )。 3.矩法估计需要知道总体的分布( )。 4.ADF 检验中:原假设序列是非平稳的( )。 5.最优模型确定准则:AIC 值越小、SC 值越大,说明模型越优( )。 6.对具有曲线增长趋势的序列,一阶差分可剔除曲线趋势( )。 7.严平稳序列与宽平稳时序区分主要表现在定义角度不同( )。 8.某时序具有指数曲线增长趋势时,需做对数变换,才能剔除曲线趋势( )。 9.时间序列平稳性判断方法中 ADF 检验优于序时图法和自相关图检验法( )。 10.时间序列的随机性分析即是长期趋势分析( )。 11.ARMA (p,q )模型是ARIMA(p,d,q)模型的特例( )。 12.若某序列的均值和方差随时间的平移而变化,则该序列是非平稳的( )。 13. MA(2)模型的3阶偏自相关系数等于0( )。 14.ARMA(p,q)模型自相关系数p 阶截尾,偏自相关系数拖尾( )。 15.MA(q)模型平稳的充分必要条件是关于后移算子B 的q 阶移动自回归系数多项式根的绝对值均在单位圆内( )。 二、填空题。(每空2分,共20分) 1.t X 满足ARMA (1,2)模型即:t X =0.43+0.341-t X +t ε+0.81-t ε–0.22-t ε,则均值= ,1θ(即一阶移动均值项系数)= 。 2.设{x t }为一时间序列,B 为延迟算子,则B 2 X t = 。 3.在序列y 的view 数据窗,选择 功能键,可对序列y 做ADF 检验。

国际金融英文版习题

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金融时间序列分析

金融时间序列分析 第一章绪论 第一节时间序列分析的一般问题 人们在日常生活和工作中会遇到大量的金融数据,如存款的利率、股票的价格、债券的收益等等, 例某支股票的价格。。。 如何从这些数据中总结、发现其变化规律,如何从这些数据中总结、发现其变化规律,从而预测或控制现象的未来行从这些数据中总结为,这就是时间序列分析这门课程所要研究的问题。 研究方式 数据建立模型预测 数据数据的类型。 横剖面数据:由若干现象在某一时点上所处的状态所形成的数据,称为横剖面数据,剖面数据,又称为静态数据。它反映一定时间、地点等客观条件下诸现象之间存在的内在数值联系。例如,上海证券交易所所有股票在某一时刻的价格;某一时刻全国各省会城市的温度,都是横剖面数据;研究方法:多元统计分析。纵剖面数据:由某一现象或若干现象在不同时点上的状态所形成的数据,称为纵剖面数据,纵剖面数据,又称为动态数据。它反映的是现象与现象之间关系的发展变化规律。例如,南京市1980 年至2005 年每年末的人口数;上海证券交易所所有股票在一年中每个周末收盘价,都是纵剖面数据研究方法:时间序列分析时间序列概念时间序列概念。时间序列:简单地说,时间序列就是按照时间顺序排成的一个数列,其中每一项的取值是随机的。严格的时间序列的定义需要随机过程的概念。设(, β , P ) 是一个概率空间,其中是样本空间,β 是上的σ -代数,P 是Copyright: Rongbao Gu, School of Finance, Nanjing University of Finance and Economics, 2006 金融时间序列分析上的概率测度。又设T 是一个有序指标集。概率空间(, β , P ) 上的随机变量{ X t : t ∈T } 的全体称为随机过程。随机过程。

时间序列期末试题B卷

系名____________班级____________姓名____________学号____________ 密封线内不答题 成都信息工程学院考试试卷 2012——2013学年第2学期 课程名称:《金融时间序列分析》 班级:金保111本01、02、03班 一、判断题(每题1分,正确的在括号内打√,错误的在括号内打×,共15分) 1.模型检验即是平稳性检验( )。 2.模型方程的检验实质就是残差序列检验( )。 3.矩法估计需要知道总体的分布( )。 4.ADF 检验中:原假设序列是非平稳的( )。 5.最优模型确定准则:AIC 值越小、SC 值越大,说明模型越优( )。 6.对具有曲线增长趋势的序列,一阶差分可剔除曲线趋势( )。 7.严平稳序列与宽平稳时序区分主要表现在定义角度不同( )。 8.某时序具有指数曲线增长趋势时,需做对数变换,才能剔除曲线趋势( )。 9.时间序列平稳性判断方法中 ADF 检验优于序时图法和自相关图检验法( )。 10.时间序列的随机性分析即是长期趋势分析( )。 11.ARMA (p,q )模型是ARIMA(p,d,q)模型的特例( )。 12.若某序列的均值和方差随时间的平移而变化,则该序列是非平稳的( )。 13. MA(2)模型的3阶偏自相关系数等于0( )。 14.ARMA(p,q)模型自相关系数p 阶截尾,偏自相关系数拖尾( )。 15.MA(q)模型平稳的充分必要条件是关于后移算子B 的q 阶移动自回归系数多项式根的绝对值均在单位圆内( )。 二、填空题。(每空2分,共20分) 1.t X 满足ARMA (1,2)模型即:t X =0.43+0.341-t X +t ε+0.81-t ε–0.22-t ε,则均值= ,1θ(即一阶移动均值项系数)= 。 2.设{x t }为一时间序列,B 为延迟算子,则B 2 X t = 。 3.在序列y 的view 数据窗,选择 功能键,可对序列y 做ADF 检验。 4.若某平稳时序的自相关图拖尾,偏相关图1阶截尾,则该拟合 模型。

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