搜档网
当前位置:搜档网 › 上海民办上宝中学八年级数学下册第一单元《二次根式》测试题(包含答案解析)

上海民办上宝中学八年级数学下册第一单元《二次根式》测试题(包含答案解析)

上海民办上宝中学八年级数学下册第一单元《二次根式》测试题(包含答案解析)
上海民办上宝中学八年级数学下册第一单元《二次根式》测试题(包含答案解析)

一、选择题

1. )

A B =± C .23<< D 2÷=

2.下列各式中,正确的是( )

A .3=

B 3=±

C 3=-

D 3=

3.已知x ,y 为实数,y 2=

,则y x 的值等于( ) A .6

B .5

C .9

D .8 4.下列运算正确的是 ( )

A B C .1)2=3-1 D

5. ) A .1个

B .2个

C .3个

D .4个

6x 的取值范围是( )

A .1≥x

B .1x >

C .1x ≤

D .1x =

7.若0

A .2x

B .- 2x

C .-2x

D .2x

8.下列计算正确的是( )

A .336a a a +=

B .1=

C .()325x x =

D .642b b b ÷= 9.下列计算正确的是( )

A =

B .8-=

C =

D 4=

10.下列二次根式中,不能..

合并的是( )

A B C D 11.函数

y =

x 的取值范围是( ). A .2x > B .2x ≠ C .2x < D .0x ≠

12.计算 )

A .-3

B .3

C .-9

D .9

二、填空题

13.当2<a <3时,化简:2a -______.

14.把四张形状大小完全相同宽为1cm 的小长方形卡片(如图①)不重叠地放在一个底面为长方形(长为21cm ,宽为4cm )的盒子底部(如图②),盒子底面未被卡片覆盖的部分用阴影表示,则图②中两块阴影部分的周长和是_________.

15.82

_____. 16.计算22(2)(3)x x -+-________.

17.化简-15827102÷31225a

=___________. 当1<x <4时,|x -221x x -+=____________.

18.比较大小:3105

19.已知8817y x x =--,则x y +的平方根为_________.

20.3x -有意义的x 的取值范围是______. 三、解答题 21.已知a ,b ,c 满足22|81025(18)0a b b c +-+=.试问以a ,b ,c 为边能否构成三角形?若能,求出其周长;若不能,请说明理由.

22.计算下列各题 (111274833

(20()

220803215- 23.计算

(1)38232182)(325)(325) 24()2

0143220202π-??+-- ??? 25.3272922-+.

26.先化简,再求值:21()111

x x x x -÷---,其中x 3.

【参考答案】***试卷处理标记,请不要删除

一、选择题

1.B

解析:B

【分析】

表示求8的算术平方根,而算术平方根是求一个非负数的正的平方根,据此可以得到结果.

【详解】

A A正确.

B、8表示求8的算术平方根,而算术平方根是求一个非负数的正的平方根,

=B错误.

<∴<.故C正确.

C、4823

D2

÷===.故D正确.

故选B.

【点睛】

本题考查了算术平方根的定义、二次根式的除法及无理数的有关概念,正确的理解算术平方根是解决此题的关键.

2.D

解析:D

【分析】

根据二次根式的性质化简判断.

【详解】

A、3

=±,故该项不符合题意;

B3

=,故该项不符合题意;

=,故该项不符合题意;

C3

=,故该项符合题意;

D3

故选:D.

【点睛】

此题考查二次根式的化简,正确掌握二次根式的性质是解题的关键.

3.C

解析:C

【分析】

直接利用二次根式的有意义的条件分析得出答案.

【详解】

解:依题意有3030x x -≥??-≥?

,解得3x =, ∴2y =,

∴239y x ==.

故选:C .

【点睛】

本题主要考查了二次根式有意义的条件,正确把握相关性质是解题关键.

4.B

解析:B

【分析】

根据各个选项中的式子,可以计算出正确的结果,从而可以解答本题.

【详解】

A A 错误;

B ,故选项B 正确;

C 、21)313=-=-,故选项C 错误;

D 53=≠+,故选项D 错误;

故选:B .

【点睛】

本题考查了二次根式的混合运算,解答本题的关键是明确二次根式混合运算的法则. 5.B

解析:B

【分析】

根据最简二次根式的定义(被开方数不含有能开的尽方的因式或因数,被开方数不含有分母),判断即可.

【详解】

解:∵2

==|x =,

?,共2个,

故选:B .

【点睛】

本题考查了对最简二次根式的理解,能熟练地运用定义进行判断是解此题的关键. 6.A

解析:A

【分析】

根据二次根式有意义的条件可得x-1≥0,再解即可.

【详解】

解:由题意得:x-1≥0,

解得:x≥1,

故选:A .

【点睛】

本题考查了二次根式有意义的条件,关键是掌握二次根式中的被开方数是非负数. 7.D

解析:D

【分析】

利用完全平方公式以及二次根式的性质,结合0

【详解】

∵0

x x >0,1-x x <0,

∴ =11|+

||-|x x x x

- =1+x x +1-x x

=2x ,

故选D

【点睛】

||a =,是解题的关键. 8.D

解析:D

【分析】

依次根据合并同类项法则,二次根式的加减、幂的乘方和同底数幂的除法判断即可.

【详解】

解:A. 3332a a a +=,故该选项错误;

B. =

C. ()32236x x x ?==,故该选项错误;

D. 64642b b b b -÷==,故该选项正确.

故选:D .

【点睛】

本题考查幂的相关计算,合并同类项和二次根式的加减.掌握相关运算法则,能分别计算是解题关键.

9.C

解析:C

【分析】

根据二次根式的加减乘除运算法则分别计算出各项的结果,再进行判断得出结论即可.

【详解】

解:A ≠

B 、8-≠

C =

D =

,原式计算错误,故不符合题意;

故选:C .

【点睛】

此题主要考查了二次根式的加减乘除运算,熟练掌握二次根式的运算法则是解答此题的关键. 10.B

解析:B

【分析】

并的二次根式.

【详解】

解:A

B 被开方数不相同,不是同类二次根式,不能进行合并,故本选项正确;

C 被开方数相同,是同类二次根式,能进行合并,故本选项错误;

D 故选B .

【点睛】

本题主要考查二次根式的化简,同类二次根式的定义,关键在于熟练掌握同类二次根式的定义,正确的对每一选项中的二次根式进行化简.

11.C

解析:C

【分析】

0≠;根据二次根式的性质,得20x -≥,从而得到自变量x 的取值范围.

【详解】

结合题意,得:

200x -≥??≠ ∴22

x x ≤??≠? ∴2x <

故选:C .

【点睛】

本题考查了分式、二次根式的知识;解题的关键是熟练掌握分式、二次根式的性质,从而完成求解.

12.A

解析:A

【分析】

根据二次根式的性质即可求出答案.

【详解】

解:原式=-3,

故选:A .

【点睛】

本题考查二次根式的性质,解题的关键是熟练运用二次根式的性质,本题属于基础题型.

二、填空题

13.2a -5【分析】直接利用绝对值的性质二次根式的性质化简求出答案【详解】∵2<a <3∴a-2>0a-3<0∴|原式=a?2-(3?a )=a-2-3+a=2a-5故答案为:2a-5【点睛】此题主要考查了

解析:2a -5

【分析】

直接利用绝对值的性质,二次根式的性质化简求出答案.

【详解】

∵2<a <3,

∴a-2>0,a-3<0,

∴|原式=a?2-(3?a )=a-2-3+a=2a-5.

故答案为:2a-5.

【点睛】

此题主要考查了二次根式的性质与化简,正确利用a 的取值范围化简是解题关键.

14.16cm【分析】根据题意分别列出关系式得出关于图②中两块阴影部分的长和宽再利用周长公式时行计算去括号合并即可得到结果【详解】解:设小长方形卡片的长为xcm小长方形卡片的宽为根据题意得:x=-2则图②

解析:16cm

【分析】

根据题意分别列出关系式,得出关于图②中两块阴影部分的长和宽,再利用周长公式时行计算,去括号合并即可得到结果.

【详解】

解:设小长方形卡片的长为xcm,小长方形卡片的宽为1cm,

根据题意得: x2,

则图②-2和2,

宽分别为:2和4-x=6

∴图②中两块阴影部分的周长和是:2

2+2)+2(2+6)=16

-16(cm).

故答案为:16cm.

【点睛】

本题主要考查了二次根式的应用,在解题时要根据题意结合图形得出两块阴影部分的长和宽是解题的关键.

15.【分析】先分母有理化然后化简后合并即可【详解】解:=2﹣=故答案为:【点睛】本题考查了二次根式的混合运算:先把二次根式化为最简二次根式然后合并同类二次根式即可在二次根式的混合运算中如能结合题目特点灵

【分析】

先分母有理化,然后化简后合并即可.

【详解】

【点睛】

本题考查了二次根式的混合运算:先把二次根式化为最简二次根式,然后合并同类二次根式即可.在二次根式的混合运算中,如能结合题目特点,灵活运用二次根式的性质,选择恰当的解题途径,往往能事半功倍.

16.【分析】利用二次根式有意义的条件得到x≤2再利用二次根式的性质化简得到原式=2﹣x+|x﹣3|然后去绝对值后合并即可【详解】解:∵∴∴故答案

为:【点睛】此题考查了二次根式的化简掌握二次根式的性质和是

解析:52x -.

【分析】

利用二次根式有意义的条件得到x≤2,再利用二次根式的性质化简得到原式=2﹣x+|x ﹣3|,然后去绝对值后合并即可.

【详解】

解:∵20x -≥,

∴2x ≤,

∴22352x x x =-+-=-.

故答案为:52x -.

【点睛】

此题考查了二次根式的化简,掌握二次根式的性质2(0)a a =≥

(0)0? (0)(0)a a a a a a >??===??-

是解答此题的关键. 17.;【分析】由二次根式的性质进行化简然后计算除法运算即可;由绝对值的意义和二次根式的性质进行化简即可求出答案【详解】解:-÷====;∵∴∴;∴;故答案为:;【点睛】本题考查了二次根式的乘除运算二次根

解析:2- 25x -+.

【分析】

由二次根式的性质进行化简,然后计算除法运算即可;由绝对值的意义和二次根式的性质进行化简即可求出答案.

【详解】 解:-15827102÷31225a

=158-

=215896a

-?÷

=2

3-

=2-

∵14x <<,

∴40x -<,10x ->,

∴44x x -=-

∴44(1)25x x x x -=---=-+;

故答案为:2-25x -+.

【点睛】

本题考查了二次根式的乘除运算,二次根式的性质,绝对值的意义,解题的关键是熟练掌握运算法则,正确的进行解题.

18.>【分析】根式比较大小:通常先转化成分数指数幂寻找分母的最小公倍数作为新的指数从而进行解题【详解】解:分母2和3的最小公倍数为6;∴由于即故所以故答案为:>【点睛】本题考查了实数的比较大小解题的关键 解析:>

【分析】

根式比较大小:通常先转化成分数指数幂,寻找分母的最小公倍数作为新的指数.从而进行解题.

【详解】 1

310=1

25=,分母2和3的最小公倍数为6; ∴1

6623(10)10100===,16632(5)5125===,

由于100125<,

即66<,

所以>.

故答案为:>.

【点睛】

本题考查了实数的比较大小,解题的关键是掌握比较大小的法则进行计算. 19.±5【分析】先根据二次根式有意义的条件求得x 的值然后再求得y 的值最后再求x+y 的平方根即可解答【详解】解:∵x-8≥08-x≥0∴x=8∴∴x+y 的平方根为故答案为±5【点睛】本题考查了二次根式的意

解析:±5

【分析】

先根据二次根式有意义的条件求得x 的值,然后再求得y 的值,最后再求x+y 的平方根即可解答.

【详解】

解:∵x-8≥0,8-x≥0

∴x=8 ∴1717y =

∴x+y 的平方根为5==±.

故答案为±5.

【点睛】

本题考查了二次根式的意义和代数式求值,根据二次根式的意义求得x 的值成为解答本题的关键.

20.且【分析】根据分式的分母不能为0二次根式的被开方数大于或等于0列出式子求解即可得【详解】由题意得:解得且故答案为:且【点睛】本题考查了分式和二次根式有意义的条件熟练掌握分式和二次根式的定义是解题关键 解析:3x ≤且2x ≠-

【分析】

根据分式的分母不能为0、二次根式的被开方数大于或等于0列出式子求解即可得.

【详解】

由题意得:2030x x +≠??-≥?

, 解得3x ≤且2x ≠-,

故答案为:3x ≤且2x ≠-.

【点睛】

本题考查了分式和二次根式有意义的条件,熟练掌握分式和二次根式的定义是解题关键.

三、解答题

21.能构成三角形,其周长为

【分析】

利用已知条件以及绝对值的性质确定a ,b ,c 的值即可,根据三角形的三边关系判断能构成三角形,然后再求周长即可.

【详解】

解:能构成三角形,

理由:∵2|(0a c =,

=0,(b-5)2=0,,

∴a

,b =5,c ;

5,

∴能构成三角形,

周长为:+5.

【点睛】

本题主要考查了绝对值;二次根式;非负数的性质,关键是掌握绝对值、算术平方根和偶次幂具有非负性.

22.(1)2)13

【分析】

(1)先将原式中的二次根式化成最简二次根式,然后再合并即可得到答案;

(2)先进行化简和根据完全平方公式去括号,再进行计算即可.

【详解】

解:(1

=13?

=

=

(2()

21

-

=

=6-

=13-

【点睛】

此题考查二次根式的混合运算,在进行此类运算时,一般先把二次根式化为最简二次根式的形式后再运算.

23.(1;(2)-17

【分析】

(1)先化简二次根式,再合并即可;

(2)利用平方差计算即可.

【详解】

解:(1)

=

(68=-+

=

(2)

22=-

320=-17=-

【点睛】

本题考查了二次根式的运算、平方差公式,准确掌握运算法则,合理利用公式是解题关键.

24.7-

【分析】 先化简二次根式、绝对值、负整数指数幂运算、零指数幂运算,再计算加减法.

【详解】

()2

01

220202π-??+-- ???

=2241+-

=7-

【点睛】

此题考查实数的混合运算,熟练掌握二次根式的化简、绝对值的化简、负整数指数幂运算、零指数幂运算是解题的关键.

25

【分析】

先计算立方根、平方根再去绝对值,合并同类二次根式与同类项进而得出答案.

【详解】

解:原式=33-+

=33-++

=

【点睛】

本考查了二次根式的混合运算,熟练掌握实数的运算法则与同类二次根式合并法则是解题的关键.

26.2x +.

【分析】

先根据分式的混合运算法则化简原式,然后再将x 的值代入计算即可.

【详解】 解:原式=2(1)11x x x x ??+?- ?--??

=2(1)1

x x x +?-- =x +2.

把x .

【点睛】

本题主要考查分式的混合运算,二次根式的加法,掌握分式的混合运算顺序和运算法则是解答本题的关键.

2020-2021上海民办上宝中学小学数学小升初模拟试卷(含答案)

2020-2021上海民办上宝中学小学数学小升初模拟试卷(含答案) 一、选择题 1.7.49亿这个数中的“4”表示() A. 4亿 B. 4000万 C. 400000 D. 400万2.口袋里有3个红球和5个白球,球除颜色外完全相同。从中任意摸出一个球,摸出红球的可能性是(). A. B. C. D. 3.要想描述六年级(3)班同学身高分组的分布情况,应选用()合适。 A. 条形统计图 B. 折线统计图 C. 扇形统计图 D. 以上都行 4.一个零件长4毫米,画在图上长12厘米。这幅图的比例尺是()。 A. 1:30 B. 1:3 C. 30:1 D. 3:1 5.一项工程,甲独立完成要30天,乙独立完成要20天,现两队合作,几天后完成了这项 工程的。如果按这样的效率,算式()可以表示求剩下的工程需要多少天完成。 A. ÷( + ) B. (1- )÷( + ) C. 1÷( + ) D. (1- )÷( - ) 6.一套科技读物原价90元,商场庆“五一”搞促销打七五折,算式()表示求现价。A. 90×75% B. 90×(1-75%) C. 90÷75% D. 90÷(1-75%)7.长沙地铁1号线和地铁2号线总里程约为50千米,2019年5月随着地铁4号线的开通,长沙地铁总里程增加了67%,地铁4号线开通后,长沙地铁总里程约为() A. 67千米 B. 117.1千米 C. 33.5千米 D. 83.5千米8.一块玉璧的形状是一个圆环,外圆半径是3cm,内圆半径是1cm,这个圆环的面积是()(π取3.14) A. 3.14cm2 B. 12.56cm2 C. 25.12cm2 D. 28.26cm2 9.甲车间的出勤率比乙车间高,以下说法正确的是() A. 甲车间的总人数一定比乙车间多 B. 甲车间的出勤人数一定比乙车间多 C. 甲车间的未出勤人数一定比乙车间少 D. 以上说法都不对 10.小明五次数学考试成绩如下表,第五次考试成绩是()分。 次别第一次第二次第三次第四次第五次平均分 成绩(分)8896939993 11.有一张方格纸,每个小方格的边长是1厘米,上面堆叠有棱长1厘米的小正方体(如左下图),小正方体A的位置用(1,1,1)表示,小正方体B的位置用(2,6,5)表示,那么小正方体 C的位置可以表示成()。

上海市上宝中学数学圆 几何综合章末训练(Word版 含解析)

上海市上宝中学数学圆几何综合章末训练(Word版含解析) 一、初三数学圆易错题压轴题(难) 1.如图所示,CD为⊙O的直径,点B在⊙O上,连接BC、BD,过点B的切线AE与CD 的延长线交于点A,OE//BD,交BC于点F,交AB于点E. (1)求证:∠E=∠C; (2)若⊙O的半径为3,AD=2,试求AE的长; (3)在(2)的条件下,求△ABC的面积. 【答案】(1)证明见解析;(2)10;(3)48 5 . 【解析】 试题分析:(1)连接OB,利用已知条件和切线的性质证明:OE∥BD,即可证明:∠E=∠C; (2)根据题意求出AB的长,然后根据平行线分线段定理,可求解; (3)根据相似三角形的面积比等于相似比的平方可求解. 试题解析:(1)如解图,连接OB, ∵CD为⊙O的直径, ∴∠CBD=∠CBO+∠OBD=90°, ∵AB是⊙O的切线, ∴∠ABO=∠ABD+∠OBD=90°, ∴∠ABD=∠CBO. ∵OB、OC是⊙O的半径, ∴OB=OC,∴∠C=∠CBO. ∵OE∥BD,∴∠E=∠ABD, ∴∠E=∠C; (2)∵⊙O的半径为3,AD=2, ∴AO=5,∴AB=4. ∵BD∥OE, ∴=, ∴=, ∴BE=6,AE=6+4=10 (3)S △AOE==15,然后根据相似三角形面积比等于相似比的平方可得

S △ABC = S △AOE == 2.已知: 图1 图2 图3 (1)初步思考: 如图1, 在PCB ?中,已知2PB =,BC=4,N 为BC 上一点且1BN =,试说明: 1 2 PN PC = (2)问题提出: 如图2,已知正方形ABCD 的边长为4,圆B 的半径为2,点P 是圆B 上的一个动点,求 1 2 PD PC +的最小值. (3)推广运用: 如图3,已知菱形ABCD 的边长为4,∠B ﹦60°,圆B 的半径为2,点P 是圆B 上的一个动点,求1 2 PD PC -的最大值. 【答案】(1)详见解析;(2)5;(3)最大值37DG =【解析】 【分析】 (1)利用两边成比例,夹角相等,证明BPN ?∽BCP ?,得到PN BN PC BP =,即可得到结论成立; (2)在BC 上取一点G ,使得BG=1,由△PBG ∽△CBP ,得到1 2 PG PC =,当D 、P 、G 共线时,1 2 PD PC + 的值最小,即可得到答案; (3)在BC 上取一点G ,使得BG=1,作DF ⊥BC 于F ,与(2)同理得到1 2 PG PC =,当点P 在DG 的延长线上时,1 2 PD PC -的值最大,即可得到答案. 【详解】 (1)证明:∵2,1,4PB BN BC ===,

2017-2018上海上宝中学九上英语期中考试(附答案)

上宝中学2017学年第一学期期中考试卷2017.11.7 Part 2 Phonetics, Grammar and Vocabulary (第二部分语音、语法和词汇) Ⅱ. Choose the best answer(选择最恰当的答案)(共20分) 26. The temperate dropped to minus ten degrees centigrade. Which of the following is correct for the underlined word? A. /'men?s/ B. /'mi:n?s/ C. /'ma?n?s/ D. /'m?n?s/ 27. I’m feeling a little depressed at the moment, but I’m sure good times are just ______. A. on the corner B. in the corner C. at the corner D. around the corner 28. The happiest are not those who _____ all the best things, but those who can appreciate the beauty of life ______. A. owns, on their own B. own, with their own hearts C. own, of their own D. own, by their own hearts 29. He is keen on scientific research but indifferent to promotion. Which of the following can’t b e used to replace the underlined part? A. is interested in B. is fond of C. is in favor of D. goes in for 30. Products produced by Apple Co. are quite popular ____ young people. A. with B. about C. in D. of 31. A mistake ______ have been made on our bill. We didn’t order any fish today. A. should B. would C. must D. can 32. The basic design of the house is very _____ that of earlier models, but ___ than it. A. same as, twice bigger B. same as, bigger twice C. similar to, twice bigger D. similar to, bigger twice 33. The fact that the examiners had failed over half the candidates discouraged us, ____? A. didn’t it B. hadn’t they C. did it D. had they 34. He is unwilling to admit ____ the assignment. A. having trouble understanding B. having trouble with understanding C. to have trouble understanding D. to have trouble with understanding 35. I’m not prepared to _____ some private matter _____. A. discuss about, by telephone B. discuss, over the telephone C. talk, on the telephone D. talk about, by the telephone 36. If the fire _____, anybody should ______ 119 at once and the firemen would come in no time. A. broke out, ring B. was broken out, phone C. broke out, dial D. was broken out, talk 37. Do not wait for good things to ______ you. You need walk towards happiness. A. happen on B. happen to C. take place on D. take place to 38. The three ______ assisted several ____ to find their hotel. A. boy volunteers, women tourists B. boy volunteers, woman tourists C. boys volunteers, women tourist D. boys volunteers, woman tourists 39. Wechat attracts ____ the people, they spend 80-90 _____ their spare time on it. A. a large percent of, percent of B. a high percent of, percentage of

2019-2020上海市上宝中学数学中考一模试题(含答案)

2019-2020上海市上宝中学数学中考一模试题(含答案) 一、选择题 1.“厉行勤俭节约,反对铺张浪费”势在必行,最新统计数据显示,中国每年浪费食物总量折合粮食大约是230000000人一年的口粮,将230000000用科学记数法表示为( ) A .2.3×109 B .0.23×109 C .2.3×108 D .23×107 2.地球与月球的平均距离为384 000km ,将384 000这个数用科学记数法表示为( ) A .3.84×103 B .3.84×104 C .3.84×105 D .3.84×106 3.将抛物线2 3y x =向上平移3个单位,再向左平移2个单位,那么得到的抛物线的解析式为( ) A .23(2)3y x =++ B .23(2)3y x =-+ C .23(2)3y x =+- D .23(2)3y x =-- 4.在“朗读者”节目的影响下,某中学开展了“好书伴我成长”读书活动.为了解5月份八年级300名学生读书情况,随机调查了八年级50名学生读书的册数,统计数据如下表所示: 册数 0 1 2 3 4 人数 4 12 16 17 1 关于这组数据,下列说法正确的是( ) A .中位数是2 B .众数是17 C .平均数是2 D .方差是2 5.如图,直线l 1∥l 2,将一直角三角尺按如图所示放置,使得直角顶点在直线l 1上,两直角边分别与直线l 1、l 2相交形成锐角∠1、∠2且∠1=25°,则∠2的度数为( ) A .25° B .75° C .65° D .55° 6.如图,将一个小球从斜坡的点O 处抛出,小球的抛出路线可以用二次函数y=4x ﹣12 x 2刻画,斜坡可以用一次函数y= 1 2 x 刻画,下列结论错误的是( )

上宝中学2018学年第一学期期中考试 上海市 英语试卷

上宝中学2018学年第一学期期中考试 Part2 Phonetics,Vocabulary and Grammar 第二部分语音,词汇和语法 II.Choose the best answer.(20分) 26.He didn’t just command.He personally fought in several healthy battles.Which of the following is correct for the underlined word. A. [k?’ma:nd] B. [k?’m?:nd] C. [ki’m?nd] D.[k?’ma:nd] 27.Which of the following underlined parts is different in pronunciation from others? A.For the first few ye ars I didn’t draw any sal ary at all. B.I’d like a full-time position with more responsibility. C. Weber gave a fair hearing to anyone who held a different opinion. D.He has served the farm faithfully for 20 years. 28.While he was investing ways to improve the telescope,Newton made _____discovery which completely changed_____man’s understanding of color. A.a;/ B. a;the C. /;the D.the;a 29.The students also take SAT and CAT_______mathematics and chemistry. A. except B. except for C. beside D.besides 30.It is not rare in______that people in_____fifties are going to university for future education. A. 90s;/ B. the 90’s;/ C.90s;their D.the 90’s;their 31.The hunter______the fox,took off its skin and_____it on the tree. A. hung;hanged B. hung;hung C. hanged;hanged D.hanged;hung 32.The room is used to____parties by the young man.He is used to_____parties here. A.holding;hold B. hold;holding C.holding;holding D.hold;hold 33.Tom must have played the guitar______if he has got one. A. Some times B. sometimes C. for some time D.sometime 34.When she was asked about the missing calculator,she_______ever seeing it. A. refused B.denied C.opposed D.pretended 35.______our country has plenty of oil,theirs has none. A. When B. While C.As D.Since 36.A library with five thousand books,______to the nation as a gift. A. is offered B. has offered C. are offered D.have offered 37.As soon as everyone taking the examination_______,the test paper were______. A. was seated;given up B.seated;given off C.sat;given in D.was seated;given out 38.The news came as no surprise to me. I_______for sometime that the factory was going to shut down. A. had known B. knew C.have known D.know 39.The taxi driver had no choice but_____help.

(完整word版)上海民办上宝中学2017学年第一学期初二第一次阶段测试英语卷(无听力部分)

上海上宝中学2017学年第一学期初二第一次阶段性测试英语卷 Part II Vocabulary and Grammar I. Choose the best answer:20’ 26. Which of the underline parts has the different pronunciation from the others? A business B luckily C assistant D simple 27. It’s _________honor for every guest to be involved to ________dinner. A. a, a B an,/ C an, the D /,/ 28. There are various kinds of _________in this river, and I have caught three ______so far. A. fish, fish B fishes, fishes C fish, fishes D fishes, fish 29. Mr. Bean as well as the other passengers ________quite angry ________the delay. A. are, with B are, about C is, with D is, at 30. ------You are always full of _________. Can you tell me the secret? ------ Taking plenty of exercise every day. A. energy B strength C force D power 31. The teacher who _______a class is a class teacher. A. is in charge of B is in the charge of C is responsibility for D in charge of 32. Since everyone is here, let’s get down to business. What does the underlined part mean? A. buying or selling goods B company C matters that need to be dealt with D trade 33. In the past few years, Dr. Sun __________great success in the field of science. A. has achieved B achieved C had achieved D achieves 34. I remember ________him 200 Yuan last week, but he forgets ______the money to me. A. lending, to return B. to lend, to return C. lending, returning D. to lend, returning 35. You are sure to learn the subject well ________ you find the right way. A. until B. through C.as long as D. unless 36. _______, you need to give all you have and try your best. A. Being a winner B. To be a winter C. Be a winner D. Having been a winner 37. He likes pop music, so he _______go to the corner tomorrow night, but I’m not sure. A. can B. may C. must D. should 38. Sorry, madam. This kind of laptops _______ out. Look! Laptops of that kind also _________well. A. have been sold, sell B. sells, have been sold C. have been sold, sold D. have been sold ,sell 39. Parents often expect their children ________all the things that they couldn’t do in the past. A. did B. doing C.to do D.do 40. It’s time to __________these foolish ideas and become serious. A. put away B. put up C. put up with D. put out 41. My brother is going to Japan ________next May and he will stay there for _______. A. some time, some times B. sometime, some time C. sometimes, some time D some times ,sometimes

2020-2021上海民办上宝中学七年级数学上期末模拟试卷(含答案)

2020-2021上海民办上宝中学七年级数学上期末模拟试卷(含答案) 一、选择题 1.若x 是3-的相反数,5y =,则x y +的值为( ) A .8- B .2 C .8或2- D .8-或2 2.将7760000用科学记数法表示为( ) A .57.7610? B .67.7610? C .677.610? D .77.7610? 3.实数a 、b 、c 在数轴上的位置如图所示,且a 与c 互为相反数,则下列式子中一定成立 的是( ) A .a+b+c>0 B .|a+b|

2017_2018上海上宝中学九上英语期中考试(附答案)

上宝中学2017学年第一学期期中考试卷 2017.11.7 Part 2 Phonetics, Grammar and Vocabulary (第二部分语音、语法和词汇) Ⅱ. Choose the best answer(选择最恰当的答案)(共20分) 26. The temperate dropped to minus ten degrees centigrade. Which of the following is correct for the underlined word? A. /'men?s/ B. /'mi:n?s/ C. /'ma?n?s/ D. /'m?n?s/ 27. I’m feeling a little depressed at the moment, but I’m sure good times are just ______. A. on the corner B. in the corner C. at the corner D. around the corner 28. The happiest are not those who _____ all the best things, but those who can appreciate the beauty of life ______. A. owns, on their own B. own, with their own hearts C. own, of their own D. own, by their own hearts 29. He is keen on scientific research but indifferent to promotion. Which of the following can’t b e used to replace the underlined part? A. is interested in B. is fond of C. is in favor of D. goes in for 30. Products produced by Apple Co. are quite popular ____ young people. A. with B. about C. in D. of 31. A mistake ______ have been made on our bill. We didn’t order any fish today. A. should B. would C. must D. can 32. The basic design of the house is very _____ that of earlier models, but ___ than it. A. same as, twice bigger B. same as, bigger twice C. similar to, twice bigger D. similar to, bigger twice 33. The fact that the examiners had failed over half the candidates discouraged us, ____? A. didn’t it B. hadn’t they C. did it D. had they 34. He is unwilling to admit ____ the assignment. A. having trouble understanding B. having trouble with understanding C. to have trouble understanding D. to have trouble with understanding 35. I’m not prepared to _____ some private matter _____. A. discuss about, by telephone B. discuss, over the telephone C. talk, on the telephone D. talk about, by the telephone 36. If the fire _____, anybody should ______ 119 at once and the firemen would come in no time. A. broke out, ring B. was broken out, phone C. broke out, dial D. was broken out, talk

2017-2018年上海市上宝中学八上第二次月考

初二(上)第二次月考数学试卷 一、填空题 1. 正比例函数图像上有两点与,则的值为____________ ()1,3-(),21a a +a 2. 若二次三项式在实数范围内不能分解因式,则m 的范围是____________ ()2132m x x +-+3. 已知反比例函数的图象经过点,则m 的值为____________2y x = (),1A m 4. 若点在反比例函数的图像上,则当函数值时,自变量(),2A m -4y x =2y ≥-x 的取值范围是____________ 5. 过反比例函数图象上一点A ,分别作轴、()0k y k x =≠x y 轴的垂线,垂足分别为B 、C ,如果的面积为3,则k 的值为____________ ABC 6. 已知点在双曲线上,且OA=4,过A 作AC 垂直(),A a b 6y x =x 轴于点C ,OA 的垂直平分线交线段OC 于B ,则ABC 的周长为____________ 7. 如图,ABC 中,∠B=22.5°,∠C=60°,边AB 的垂直平分线交BC 于D ,交AB 于E ,已知,则的面积为____________ BD =ABC 8. 如果要通过平移直线得到的图像,那么直线13y x =-53x y --=13 y x =-必须向____平移____个单位 9. 关于的一次函数x ()313 y m x m =--+的图像不过第四象限,则试求m 的取值范围____________ 10. 直线交轴、轴于A 、B 两点,P 是反比例函数6y x =-x y ()40y x x =>图象上位于直线下方的一点,过点P 作轴的垂线,垂足为点M ,交AB 于点E ,过点P 作x 轴的垂线,垂足为点N ,交AB 于点F 。则____________ y AF BE ?=11. 如图4,已知在ABC 中,AB=AC ,∠A=120°,AC 的垂直平分线分别交AC 、BC 于点D 、E ,若设,DE x =,求与之间的关系式____________ BC y =y x 12. 如图5,直线与双曲线交于A 、B 两点,其横坐标分别为1和5,则不等式1y k x b =+2k y x = 的解集是____________21k k x b x +≤

上海民办上宝中学数学三角形解答题同步单元检测(Word版 含答案)

上海民办上宝中学数学三角形解答题同步单元检测(Word 版 含答案) 一、八年级数学三角形解答题压轴题(难) 1.直线MN 与直线PQ 垂直相交于O ,点A 在直线PQ 上运动,点B 在直线MN 上运动. (1)如图1,已知AE 、BE 分别是∠BAO 和∠ABO 角的平分线,点A 、B 在运动的过程中,∠AEB 的大小是否会发生变化?若发生变化,请说明变化的情况;若不发生变化,试求出∠AEB 的大小. (2)如图2,已知AB 不平行CD ,AD 、BC 分别是∠BAP 和∠ABM 的角平分线,又DE 、CE 分别是∠ADC 和∠BCD 的角平分线,点A 、B 在运动的过程中,∠CED 的大小是否会发生变化?若发生变化,请说明理由;若不发生变化,试求出其值. (3)如图3,延长BA 至G ,已知∠BAO 、∠OAG 的角平分线与∠BOQ 的角平分线及延长线相交于E 、F ,在△AEF 中,如果有一个角是另一个角的3倍,试求∠ABO 的度数. 【答案】(1)135°;(2)67.5°;(3)60°, 45° 【解析】 【分析】 (1)根据直线MN 与直线PQ 垂直相交于O 可知∠AOB=90°,再由AE 、BE 分别是∠BAO 和∠ABO 的角平分线得出1BAE OAB 2∠=∠,1 ABE ABO 2 ∠=∠,由三角形内角和定理即可得出结论; (2)延长AD 、BC 交于点F ,根据直线MN 与直线PQ 垂直相交于O 可得出∠AOB=90°,进而得出OAB OBA 90∠+∠=? ,故PAB MBA 270∠+∠=?,再由AD 、BC 分别是∠BAP 和∠ABM 的角平分线,可知1BAD BAP 2∠= ∠,1 ABC ABM 2 ∠=∠,由三角形内角和定理可知∠F=45°,再根据DE 、CE 分别是∠ADC 和∠BCD 的角平分线可知 CDE DCE 112.5∠+∠=?,进而得出结论; (3))由∠BAO 与∠BOQ 的角平分线相交于E 可知 1EAO BAO 2∠=∠,1 EOQ BOQ 2 ∠=∠ ,进而得出∠E 的度数,由AE 、AF 分别是∠BAO 和∠OAG 的角平分线可知∠EAF=90°,在△AEF 中,由一个角是另一个角的3倍分四种情况进行分类讨论. 【详解】 (1)∠AEB 的大小不变, ∵直线MN 与直线PQ 垂直相交于O ,

上海名校英语--上宝中学初一(上)U1语法测试卷

Part1 Grammar and Vocabulary Ⅰ. Choose the best answer:(9分) 26.It____ six hours and a half to travel from Shanghai to Tibet. A.costs B. spends C.takes D. Pays 27.The Wang family_____ to Bali Island twice. A.Went B. has been C.has gone D.have been 28.Singapore is_____ the south-west of Japan. A. to B. on C.in D.at 29.He’s got two tickets _____ the concert tonight. Would you like to go with him? A.to B. for C. about D. Of 30.At last they found a hotel________. A.to stay B. to live C.to stay in D. to live in 31.______ useful piece of information we found on the Internet! A.What B. How C. What a D. How an 32.I haven’t ____ John since he went to France for futher study. A.received from B. heard C. written a letter D. heard from 33.The writer put some pictures beside the article to keep the readers _____. A.interesting B.interested C. interest D. Interestingly 34._____ the end of last summer, the housing price in Shanghai_____ about 10%. A.At, had been raised B. By, had risen C. In, had risen D. On, had been raised 35.The student _____ from the chair to ask how the money _____ for the charity would be used. A.rose, raising B.rose, raised C. raised, rose D. raised, rising 36.The tour guide suggests we______ at the weekend. A.will back B. should back C. be back D.will be back 37.The disabled are thankful______ the volunteer______ helping them cross the road. A. for, to B. to, for C. for, for D. to,to 38. I don’t think the question of______ they are old or young is important. A. which B. whether C. how D. Why 39. I have no idea______. A. what does this sign means B. what this sign means C. what the meaning of this sign D. what kind of a meaning is this sign 40.I’m afraid I can’t _____ to go on holiday because I lost my job last week. A. take B. cost C. spend D. Afford 41.If Tony isn’t careful enough with his lesson, more mistakes ______ later. A.have made B. will make C. have been made D. will be made 42.______ you have been in America for many times, you must know something about this country. A.Since B. Although C. Unless D.When 43.Would you mind helping me with the heavy box? _______. A.Never mind B. Certainly not C. It’s OK. I’m strong. D. No, I can’t. Ⅱ. Phonetic symbols and word transformation: (8分) 44.The ______ offers a wide choice of hotels, apartments and holiday homes.[?b r????(r)] 45. They believed _____ Greece and Rome were vital sources of learning.[?e?n??nt] 46. Franklin joined her and the children whenever his crowded ______ allowed.[?k?l ind?] 47. _____ investors around the world have become worried about China’s economy.(nation) 48. An art ____ and collector, he was also a practising architect.(history)

上海民办上宝中学数学几何图形初步同步单元检测(Word版 含答案)

一、初一数学几何模型部分解答题压轴题精选(难) 1.如图 1,CE 平分∠ACD,AE 平分∠BAC,且∠EAC+∠ACE=90°. (1)请判断 AB 与 CD 的位置关系,并说明理由; (2)如图2,若∠E=90°且AB 与CD 的位置关系保持不变,当直角顶点E 移动时,写出∠BAE 与∠ECD 的数量关系,并说明理由; (3)如图 3,P 为线段 AC 上一定点,点 Q 为直线 CD 上一动点,且 AB 与 CD 的位置关系保持不变,当点 Q 在射线 CD 上运动时(不与点 C 重合),∠PQD,∠APQ 与∠ BAC 有何数量关系?写出结论,并说明理由. 【答案】(1),理由如下: CE 平分,AE 平分, ; (2),理由如下: 如图,延长AE交CD于点F,则 由三角形的外角性质得: ; (3),理由如下:

,即 由三角形的外角性质得: 又,即 即. 【解析】【分析】(1)根据角平分线的定义、平行线的判定即可得;(2)根据平行线的性质(两直线平行,内错角相等)、三角形的外角性质即可得;(3)根据平行线的性质(两直线平行,同旁内角互补)、三角形的外角性质、邻补角的定义即可得. 2.如图AB∥CD,点H在CD上,点E、F在AB上,点G在AB、CD之间,连接FG、GH、HE,HG⊥HE,垂足为H,FG⊥HG,垂足为G. (1)求证:∠EHC+∠GFE=180°. (2)如图2,HM平分∠CHG,交AB于点M,GK平分∠FGH,交HM于点K,求证:∠GHD=2∠EHM. (3)如图3,EP平分∠FEH,交HM于点N,交GK于点P,若∠BFG=50°,求∠NPK的度数. 【答案】(1)解:∵HG⊥HE,FG⊥HG ∴FG∥EH, ∴∠GFE+∠HEF=180°, ∵AB∥CD ∴∠BEH=∠CHE ∴∠EHC+∠GFE=180°

相关主题