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2019年上海市上宝中学初一上学期期末数学试卷(附答案)

2019年上海市上宝中学初一上学期期末数学试卷(附答案)
2019年上海市上宝中学初一上学期期末数学试卷(附答案)

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上海民办上宝中学数学几何图形初步同步单元检测(Word版 含答案)

一、初一数学几何模型部分解答题压轴题精选(难) 1.如图 1,CE 平分∠ACD,AE 平分∠BAC,且∠EAC+∠ACE=90°. (1)请判断 AB 与 CD 的位置关系,并说明理由; (2)如图2,若∠E=90°且AB 与CD 的位置关系保持不变,当直角顶点E 移动时,写出∠BAE 与∠ECD 的数量关系,并说明理由; (3)如图 3,P 为线段 AC 上一定点,点 Q 为直线 CD 上一动点,且 AB 与 CD 的位置关系保持不变,当点 Q 在射线 CD 上运动时(不与点 C 重合),∠PQD,∠APQ 与∠ BAC 有何数量关系?写出结论,并说明理由. 【答案】(1),理由如下: CE 平分,AE 平分, ; (2),理由如下: 如图,延长AE交CD于点F,则 由三角形的外角性质得: ; (3),理由如下:

,即 由三角形的外角性质得: 又,即 即. 【解析】【分析】(1)根据角平分线的定义、平行线的判定即可得;(2)根据平行线的性质(两直线平行,内错角相等)、三角形的外角性质即可得;(3)根据平行线的性质(两直线平行,同旁内角互补)、三角形的外角性质、邻补角的定义即可得. 2.如图AB∥CD,点H在CD上,点E、F在AB上,点G在AB、CD之间,连接FG、GH、HE,HG⊥HE,垂足为H,FG⊥HG,垂足为G. (1)求证:∠EHC+∠GFE=180°. (2)如图2,HM平分∠CHG,交AB于点M,GK平分∠FGH,交HM于点K,求证:∠GHD=2∠EHM. (3)如图3,EP平分∠FEH,交HM于点N,交GK于点P,若∠BFG=50°,求∠NPK的度数. 【答案】(1)解:∵HG⊥HE,FG⊥HG ∴FG∥EH, ∴∠GFE+∠HEF=180°, ∵AB∥CD ∴∠BEH=∠CHE ∴∠EHC+∠GFE=180°

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