常用Java算法面试题

Java算法面试题
文章分类:招聘求职 关键字: 算法
1.比较两个字符串如果不等返回True？


答案：
Java代码
package com.test.kaoshi;

public class StringDemo {

private static String a = "abc";
private static String b = "abcg";

public static boolean equalString() {
if (a.equals(b)) {
return false;
} else {

return true;
}
}
public static void main(String[] args) {
StringDemo sd = new StringDemo();
System.out.println("主要考察返回Boolean变量和字符串比较使用的方法?+sd.equalString());
}
}

package com.test.kaoshi;

public class StringDemo {

private static String a = "abc";
private static String b = "abcg";

public static boolean equalString() {
if (a.equals(b)) {
return false;
} else {

return true;
}
}
public static void main(String[] args) {
StringDemo sd = new StringDemo();
System.out.println("主要考察返回Boolean变量和字符串比较使用的方法?+sd.equalString());
}
}





2.随机产生20个字符并且排序？

答案：
Java代码
package com.test.kaoshi;

import java.util.HashSet;
import java.util.Iterator;
import java.util.Random;
import java.util.Set;
import java.util.TreeSet;

public class RadomDemo {
/**
* 随机产生20个字符串并且字符串不能重复 且进行排序
* @param random
* @param len
* @return
*/
public Set getChar(){

Set numberSet01 = new HashSet();
Random rdm = new Random();
char ch;
while(numberSet01.size()<20){
int rdGet = Math.abs(rdm.nextInt())%26+97;//产生97到122的随机数a-z值
ch=(char)rdGet;
numberSet01.add(ch);
//Set中是不能放进重复的值的，当它有20个时，就满足你的条件了
}
return numberSet01;
}
public static void main(String[] args) {
RadomDemo rd = new RadomDemo();
Set numberSet01=rd.getChar();

Set numberSet = new TreeSet();
numberSet.addAll(numberSet01);
for(Iterator it=numberSet01.iterator();it.hasNext();){
System.out.print(it.next());
}
System.out.println();
for(Iterator it=numberSet.iterator();it.hasNext();){
System.out.print(it.next());
}
}
}

package com.test.kaoshi;

import java.util.HashSet;
import java.util.Iterator;
import java.util.Random;
import java.util.Set;
import java.util.TreeSet;

public class RadomDemo {
/**
* 随机产生20个字符串并且字符串不能重复 且进行排序
* @param random
* @param len
* @return
*/
publ

ic Set getChar(){

Set numberSet01 = new HashSet();
Random rdm = new Random();
char ch;
while(numberSet01.size()<20){
int rdGet = Math.abs(rdm.nextInt())%26+97;//产生97到122的随机数a-z值
ch=(char)rdGet;
numberSet01.add(ch);
//Set中是不能放进重复的值的，当它有20个时，就满足你的条件了
}
return numberSet01;
}
public static void main(String[] args) {
RadomDemo rd = new RadomDemo();
Set numberSet01=rd.getChar();

Set numberSet = new TreeSet();
numberSet.addAll(numberSet01);
for(Iterator it=numberSet01.iterator();it.hasNext();){
System.out.print(it.next());
}
System.out.println();
for(Iterator it=numberSet.iterator();it.hasNext();){
System.out.print(it.next());
}
}
}


3.50个人围成一圈数到三和三的倍数时出圈，问剩下的人是谁？在原来的位置是多少？


答案：

Java代码
package com.test.kaoshi;

import java.util.Iterator;
import java.util.LinkedList;

public class YouXi {
public static int removeNM(int n, int m) {
LinkedList ll = new LinkedList();
for (int i = 0; i < n; i++)
ll.add(new Integer(i + 1));
int removed = -1;
while (ll.size() > 1) {
removed = (removed + m) % ll.size();
ll.remove(removed--);
}
return ((Integer) ll.get(0)).intValue();
}

public static void main(String[] args) {
System.out.println(removeNM(50, 3));
}
}