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GMAT网络课程语法笔记(11)

1. Temporary-employment agencies benefit not only from the increasing demand for clerical workers but also the higher profits made when highly paid professionals are placed, requests for whom have increased in the recent wave of corporate takeovers.

(A) the higher profits made when highly paid professionals are placed, requests for whom

(B) the higher profits that are made in the placement of highly paid professionals, requests for whom

(C) from the requests for highly paid professionals, who make higher profits for the agencies when placed and whose requests

(D) from highly paid professionals, whose placement makes higher profits for the agencies and whose requests

(E) from the higher profits made in placing highly paid professionals, requests for whom

2. In December of 1987 an automobile manufacturer pleaded no contest to criminal charges of

odometer tampering and agreed to pay more than $16

million in civil damages for cars that were test-driven with their odometers disconnected.

(A) cars that were test-driven with their odometers disconnected

(B) cars that it had test-driven with their disconnected odometers

(D) having test-driven cars with their odometers disconnected

(E) having cars that were test-driven with disconnected odometers

3. The bank acknowledged that they are and will continue to experience difficulties as it attempts to deal with the precipitous fall of the dollar against the yen and the dislocations reflected in the stock market decline.

(A) they are and will continue to experience difficulties as it attempts

(B) they are and will continue to experience difficulties as they attempt

(D) it is experiencing and will continue to experience difficulties as they make an attempt

(E) its difficulties are likely to continue as it attempts

4 In terms of physics, the characteristic feature of the roller coaster is that the cars' potential energy, gained through their being lifted by a chain drive through the Earth's gravity to the top of the first drop, has been converted to kinetic energy by the time the ride ends.

(A) cars' potential energy, gained through their being lifted by a chain drive

(B) cars' potential energy, a gain achieved as they are lifted by a chain drive

(D) potential energy of the cars, gained as a chain drive lifts them

(E) potential energy gained by the cars, being achieved while a chain drive lifts them

5. According to some analysts, whatever its merits, the proposal to tax away all capital gains on

short-term investments would, if enacted, have a

disastrous effect on Wall Street trading and employment.

(A) its merits, the proposal to tax

(B) its merits may be, the proposal of taxing

(D) the proposal's merits, to tax

(E) the proposal's merits are, taxing

6 The key to control over the Eurasian steppes lay in the nomad's ability to use the horse both as a means of transport but also as an effective military tool.

(A) but also as

(B) or as

(D) or

(E) and also

7 Judge Lois Forer's study asks why do some litigants have

a preferred status over others in the use of a public resource, the courts, which in theory are available to all but in fact are unequally distributed among rich and poor.

(A) do some litigants have a preferred status over others in the use of a public resource, the

courts, which in theory are available to all but in fact are unequally distributed among

(B) some litigants have a preferred status over others in the use of a public resource, the

courts, which in theory are available to all but in fact are unequally distributed between

courts, in theory available to all but in fact are unequally distributed among

(D) some litigants have a preferred status to another in the use of a public resource, the courts, in theory available to all but in fact not equally distributed between

(E) does one litigant have a preferred status over the other in the use of a public resource, the

courts, in theory available to all but in fact they are not equally distributed among

8. As litigation grows more complex, the need that experts explain technical issues becomes more

apparent.

(A) that experts explain technical issues becomes

(B) for experts to explain technical issues became

(D) that technical issues be explained by experts became

(E) that there be explanations of technical issues by experts has become

9. Last spring a Colorado health department survey of 72 playgrounds in private child-care centers

found unsafe conditions in 95 percent of them and they ranged from splinters to equipment near collapse.

(A) unsafe conditions in 95 percent of them and they ranged

(B) conditions in 95 percent were unsafe and ranging

(D) that 95 percent had unsafe conditions ranging

(E) that 95 percent of them had conditions that were unsafe; the range was

10.The expected rise in the price of oil could be a serious impact to industrialized nations and severely diminish the possibility to have an economy free of inflation.

(A) be a serious impact to industrialized nations and severely diminish the possibility to have

(B) seriously impact on industrialized nations and severely impede the possibility to have

(D) have a serious impact on industrialized nations and severely impede the possibility to have

(E) have a serious impact on industrialized nations and severely diminish the possibility of having

11. Recent excavations suggest that the ancient peoples of the Italian peninsula merged the cult of Damia---a goddess of fertility and the harvest---with Venus.

(A) with Venus

(B) and Venus

(D) and Venus'

(E) and Venus' cult

【

Word 是学生和职场人士最常用的一款办公软件之一，99.99%的人知道它，但其实，这个软件背后，还有一大批隐藏技能你不知道。掌握他们，你将开启新世界的大门。

Tab+Enter,在编过号以后，会自动编号段落

Ctrl + D调出字体栏，配合Tab+Enter全键盘操作吧

Ctrl + L 左对齐，Ctrl + R 右对齐，Ctrl + E 居中

Ctrl + F查找，Ctrl + H 替换。然后关于替换，里面又大有学问！

有时候Word文档中有许多多余的空行需要删除，这个时候我们可以完全可以用“查找替换”来轻松解决。打开“编辑”菜单中的“替换”对话框，把光标定位在“查找内容”输入框中，单击“高级”按钮，选择“特殊字符”中的“段落标记”两次，在输入框中会显示“^P^P”，然后在“替换为”输入框中用上面的方法插入一个“段落标记”(一个“^P”)，再按下“全部替换”按钮。这样多余的空行就会被删除。

Ctrl + Z是撤销，那还原呢？就是Ctrl + Y，撤销上一步撤销！

比如我输入abc, 按一下F4, 就会自动再输入一遍abc

GMAT数学知识点小结

GMAT数学知识点小结虽然对于中国考生而言，GMAT数学这些理论早已熟知于心，但涉及到全英文的考试并出现在GMAT数学真题中考生就不能掉以轻心了，接下来小编就把GMAT数学知识点为大家介绍一下，希望考生能够参考。顺利备考GMAT数学考试。加法原则和乘法原则：问自己这个事儿完成了没有？如果完成了就是加法原则，没有完成就是乘法原则。例子：从北京到上海可以乘飞机(3种方案)，轮船(2种方案)，或者火车(5种方案)，问从北京到上海乘这3种交通工具共几种方案？答：既然任何一个方案都已经到达了上海，这件事儿已经完成了，所以用加法原则：3+2+5=10种。例子：从北京到上海有2条路线，从上海到深圳有5条路线，问从北京出发经由上海到深圳会有多少种路线？答：当你到达上海时还没有到达深圳呢，没有完成，那就乘起来，用乘法原则：2 ×5=10。求最大公约数的方法：辗转相除法辗转相除法就是当你求AB两个数的最大公约数时你先用大数去被小数除，除完得到一个余数，下一步，你用上一步中那个较小的数去被上一步中的余数除，再得到余数，再继续重复这个步骤直到你用一个除数被余数除时余数为0，在最后这一步中的除数就是AB的最大公约数。整除，余数，因子数的概念：如何求一个数共有多少个不同的factor(因子)？将这个数写成它质因子幂指数相乘的形式，然后将每一个质因子的幂加一，然后彼此相乘，就得到了这个数包括1和它本身在内的所有因子个数：任一个自然数n，它的因子个数如果是偶数的话，那么它的因子个数中有一半儿因子小于根号下的n，有一半儿大于根号下的n。如果一个自然数m它的因子个数是奇数的话，它就必然是一个完全平方数，且根号下m就是它的一个因子。当你得到m的因子数后，若是a个的话，它所有的因子必然有(a-1)/2个是小于根号

Manhattan总结(中文)——GMAT语法

Chapter 1 SC Basics (1) Chapter 2 GRAMMAR, MEANING, CONCISION (1) Chapter 3 SUBJECT-VERB AGREEMENT (3) Chapter 4 PARALLELISM (5) Chapter 5 PRONOUNS (6) Chapter 6 MODIFIERS (8) Chapter 7 Verb tense , mood, & voice strategy (11) Chapter 8 comparison strategy (13) Chapter 9 Idioms——看原书 Chapter 10 Odds & ends (15) Chapter 11 GMC/S-V /PARALLELISM: ADVANCED (18) Chapter 12 pronouns & modifiers: advanced (19) Chapter 13 verbs & comparisons：advanced (22) Chapter 1 SC Basics 1、各个选项中最好的答案并不一定是完全正确、完美的 2、日常口语中实际上有很多语法错误 3、SC的做题方法：将每个选项逐个代入句子读一遍再寻找错误是很费时间的，更好的方法应该是使用分类排除的方法（split）。将五个选项按照某个语法点的区别分成两组或更多，找到你所确认的错误排除其中的一些组；再次分组，再次排除，直到剩下最终答案。 4、在一道题中将会测试多个语法点，平常练习中需要找出所有的点，而在考试时只需要找到一个能排除该选项的即可；而且每个选项往往都有多个点可以将其排除。 5、注意划线外部分，注意划线部分与划线外部分的关系，有许多重要的线索在远离划线部分的地方。选择一个选项后要重读一遍句子,确认选项使得句子完整。 Chapter 2 GRAMMAR, MEANING, CONCISION 1、在做SC时，判断选项是否错误应该从语法开始，然后考虑意思，最后考虑简洁。语法：GMAT测试你区分好和不好的语法的能力。许多语法错误的句子看起来很自然。意思：句子不能有歧义，并且句子必须反映作者的真实的意愿，在选择选项时不要随便改变句子的原意（除非原句错误）。简洁：不使用多余的词。 2、GRAMMAR：包括主谓一致、平行、代词、修饰语、时态、语气语态、比较、惯用语。 3、MEANING：不要随便改变句子原意。GMAT考试中，意思上的小错误常常容易被忽略。在MEANING上的主要考点主要可以归类为：选择正确的词、词的正确位置和词与词之间的一致。（1）选择正确的词：常考的是相近的词相互替代而使句子意思发生改变。如：

五大法宝拿下GMAT数学满分

1 五大法宝拿下GMA T 数学满分 GMA T 数学满分难么?其实一点都不困难，考生只要能够认真进行GMA T 数学备考，并掌握一定的解题技巧，那么GMA T 数学考试高分往往显得触手可及。一、数形结合。要想拿到GMA T 数学满分，第一个思想就是数形结合的思想，其实质是将抽象的数学语言与直观的图形结合起来，使抽象思维和形象思维结合，通过对图形的认识，数形结合的转化，可以培养思维的灵活性，形象性，使问题化难为易，化抽象为具体. 通过“形”往往可以解决用“数”很难解决的问题. 二、换元。换元法又称变量替换法，即根据所要求解的式子的结构特征，巧妙地设置新的变量来替代原来表达式中的某些式子或变量，对新的变量求出结果后,返回去再求出原变量的结果.换元法通过引入新的变量，将分散的条件联系起来，使超越式化为有理式、高次式化为低次式、隐性关系式化为显性关系式，从而达到化繁为简、变未知为已知的目的. 三、转化与化归。所谓转化与化归思想方法，就是在研究和解决有关数学问题时，采用某种手段将问题通过变换使之转化，进而达到解决的一种方法.一般总是将复杂的问题通过转化为简单的问题，将难解的问题通过变换转化为容易的问题，将未解决的问题变换转化为已解决的问题. 转化与化归的思想方法是数学中最基本的思想方法.数学中一切问题的解决都离不开转化与化归，数形结合思想体现了数与形的相互转化;函数与方程思想体现了函数、方程、不等式间的相互转化;分类讨论思想体现了局部与整体的相互转化，以上三种思想方法都是转化与化归思想的具体体现.各种变换法、分析法、反证法、待定系数法、构造法等都是转化的手段.所以说转化与化归是数学思想方法的灵魂. 四、函数与方程。函数思想指运用函数的概念和性质，通过类比、联想、转化、合理地构造函数，然后去分析、研究问题，转化问题和解决问题.方程思想是通过对问题的观察、分析、判断等一系列的思维过程中，具备标新立异、独树一帜的深刻性、独创性思维，将问题化归为方程的问题，利用方程的性质、定理，实现问题与方程的互相转化接轨，达到解决问题的目的. 五、分类讨论。要想拿到GMA T 数学满分，不得不提一提分类讨论。所谓分类讨论，就是当问题所给的对象不能进行统一研究时，我们就需要对研究的对象进行分类，然后对每一类分别研究，得出每一类的结论，最后综合各类的结果得到整个问题的解答.实质上分类讨论是“化整为零，各个击破，再积零为整”的策略. 分类讨论时应注重理解和掌握分类的原则、方法与技巧、做到“确定对象的全体，明确分类的标准，分层别类

GMAT曼哈顿语法---精华汇总

曼哈顿 SC 总结 Chapter 1 Sentence Correction Basics 1.一道例题 Although William Pereira first gained national recognition for his movie set designs, including those for the 1942 film "Reap the Wild Wind",future generations remember him as the architect for the Transamerica Tower, the Malibu campus of Pepperdine University and the city of Irvine. A:including those for the 1942 film "Reap the Wild Wind",future generations B: like that for the 1942 film "Reap the Wild Wind",future generations will C:like those for the 1942 film "Reap the Wild Wind",future generations D: including that for the 1942 film "Reap the Wild Wind",future generations will E:including those for the 1942 film "Reap the Wild Wind",future generations will 这道题用两点split。 1.1GMAT规定，Like不能用于举例；注意，在之后的说明中，曼哈顿说The GMAT used to claim that ‘like’ simply meant‘similar to’ and could not introduce examples. However, the exam writers have moderated this hardline duty in published explanations. As a result, either ‘including’ or‘likelihood would technically work in the sentence. 1.2GMAT规定，进行指代时，如果有单复数转换，不能用代词指代，而应换作相对应的名词。 2.做题时间一般不多于90秒钟，理想状况下，花费60-75秒。 3.做题步骤 3.1细读原文理解原文中作者本意，顺带看是否有错误出现。如发现错误，默默记下，以备之后作为排除依据；如未发现错误，不要留恋，只要保证理解了文字的字面意思和作者本意即可。 3.2纵向扫描，找split 不要读选项，只是纵向寻找不同点（split）。看句首和句尾，此两处必有split，不然画线不会画到它们。迅速找到多个split，找最容易区分的。 3.3选取最简单split进行筛选所谓简单，就是容易找/容易比较/容易决定。语法语义两个角度来分析 3.4选定第一个split 3.5用同一个split，去检查其他选项是否也犯了同样的错误

GMAT数学的难点总结

GMAT数学的难点总结数学分数不理想，这是为什么虽然GMAT数学题整体不难，但是这并不能否定部分难点，否则就否定了GMAT存在的意义。今天天道教育想和大家探讨一下GMAT数学的三大难题。一、GMAT数学科目简介 GMAT数学部分主要有两类多选题型——问题求解(ProblemsSolving简称“PS”)和数据充分性判断(DataSufficiency 简称“DS”)。GMAT数学部分主要测试考生进行数理推断、解决数学问题和解读图形数据的能力。问题求解和数据充分性判断两类问题都需要有关算术、基础代数和常见几何概念的知识。二、GMAT数学三大难题 GMAT数学难度多大GMAT数学题的虽然考点十分简单，但是抱着满分必胜信心的同学却未必能如愿以偿，归根到底有三大难题。 1、三大难题之一：读题问题。数学好的同学不一定能在GMAT数学考试中取得好成绩，因为不能把数学题目很好地转化成中文理解题意。读不懂，读得慢，回读，反复读的现象，这样不仅浪费了时间，更严重阻碍了解题思路的构建，最终导致正确率下降。克服方法： 1)加强词汇积累——背会数学词汇，放弃无关词汇。词汇是克服读题的基础，也是最容易提升的方面。首先，中文与英文的数学表达习惯有很大的区别，所以牢记固定用法是不变真理。

其次，在数学题中还会出现一些无关词汇，这些词汇只与题目所描述的场景有关，对解题不产生任何的影响。我们如果认识就直接理解，如果不认识，直接提炼首字母即可做题，不要浪费时间去理解。 2)提高读题速度——养成记笔记的习惯。读题速度慢、回读等现象大大影响了同学们做题速度。当一道题目里面的信息量过大，而且题目相对复杂时忘记在所难免。记笔记可以在每读完一句话就把这句话里面的信息点和数字简单地记下来，把英文转化成数学表达式，这样等到读完题目后，草稿纸上显示的就是整道题目完整的脉络和信息点，看着笔记立刻就可以开始做题。 2、三大难题之二：思维问题。对于习惯了国内考试套路的同学来说，经常会有一颗“提防陷阱的心”，因为国内在中高考这些国内数学考试中，出题人会大量的给考生设置陷阱，诱导一部分人犯错，从而拉开考生档次。然而GMAT 数学考试却和国内考试不同，旨在考查考生对基本数学概念的理解和基本数学技能的应用，而不是又到学生落入陷阱。而且美国人数学思维本身较差，考察点十分直接明了，所以大家不必过于“担心”。 1)解题想得太多——解题直击考点。对于任何一道GMAT数学题，大家要做的就是读懂这道题，找到这道题的核心，理解出题人想要考察的方面。除此之外其他一切都无需多想。此外，做错的题目一定要总结错误原因。对于由思维方式差异而导致的错题，一定要去看题目的讲解，然后对比自己的思路与出题人的思路，找到差异，总结考点。

GMAT数学精华题型解析(3)

A construction company was paid a total of $500,000 for a construction project. The company's only costs for the project were for labor and materials. Was the company's profit for the project greater than $150,000 ? (1) The company's total cost was three times its cost for materials. (2)The company's profit was greater than its cost for labor. 【答案】C 53. 4392-!-item-!-187;#058&003851 If wx = y, what is the value of xy ? (1) wx2 = 16 (2) y = 4 【答案】A 64. 5320-!-item-!-187;#058&004563 Are at least 10 percent of the people in Country X who are 65 years old or older employed? (1) In Country X, 11.3 percent of the population is 65 years old or older. (2) In Country X, of the population 65 years old or older, 20 percent of the men and 10 percent of the women are employed.(陷阱) 【答案】B

GMAT数学题库经典真题汇总

GMAT数学题库经典真题汇总说到GMAT数学题，下面小编为大家整理了GMAT数学题库经典真题汇总的十道题，供考生们参考，以下是详细内容。 1.一枚硬币向上抛，两面的机率各为一半，问连抛三次，同一面的机率。(1/4) 同一面有两种情况：故1/8+1/8=1/4 2. 11球，6红，5蓝，without replacement, 问取一蓝一红的possibility. 6/11 第一次取蓝的情况C15*C16 .第一次取红的情况: C16*C15，总共的情况为C111C110=110 则概率为60/110=6/11 3. 大于700的三位整数中，有多少是奇数，要求每个数字都不为零，且每位数字都不同。答案：91 How to get the answer? 4. is xy>z? 我觉得是C (1). xyz=1 (2). xyz^2>1 KEY: e why not C? (as NOT is also an answer) 5.X,Y,Z是三角形的三个边, 且X2^1/2) .1/2XYsin(a)=1 而1/2XYsin(a)<1/2Y^2sin(a) 故1<1/2Y^2sin(a) => Y^2>2/sin(a)>2 所以Y>2^1/2 6. O

X X X X X X X X X X X X X X M M M M 上图第一行"O"表一小球, 第2,3,4行的"X"表障碍物, 第6行表小槽. 小球从上落下,在第三行时受到障碍物的阻止, 其向左或右的机率相等, 各占50%. 以下依然. 问最后球掉到第六行的第二个 M的机率? (3/8) 对每一行落到X的概率都表示出来，然后即可得出结论为3/8 7. TWO KEYS，放到已有5把钥匙chain中，问这两把钥匙相邻的概率? NO.3 应该是环形的. 上面答案是机井上的. 我的答案是5/P2,10 = 1/9 不知对吗?在环形CHAIN上, 共有五个空位, 每个可放一个或二个KEY, 可得P2,10 相临情况为五个.得到1/9 8.给出标准方差公式，有一组数1，3，5，7。。。19 ，现在变动一下，问新表准方差A，B，C，D，E的MEAN是16，E为40，且E>D>C>B>A，求C的最大可能值? 标准差的公式为: sqrt((a1-a)^2+(a2-a)^2+...+(an-a)^2) 其中a=(a1+a2+..+an)/n，。怎么变动?你没说啊

Ron 笔记 gmat 语法

Ron 笔记 1、平行 first two both 2 are correct ＊the parallel structures are indicated by “parallel tags” Most fossils of species X were found in Tennessee or Kentucky Most fossils of species x were found in T or in K. FOLLOW the tags are included. *proceed from RIGHT to LEFT in your analysis Look at the words following the tag

tags: the list of 3 or more items, the COMMAS and the “AND” are tags!! Focus on the sentence ” ITS ”

USAGE OF “COMPARED TO/WITH” with statistics/quantities: *DO NOT include any other words of comparison “28 percent of American husbands were married to wives with more years of schooling, compared to 6 percent in 1971.” NO additional word re: ” more “ “ less” ”N times” etc

GMAT常用数学符号与英文解释

+ plus, positive －minus, negative ×multiplied by, times ÷(／) divided by = is equal to, equals ≠ not equal to ≈ is approximately equal to, approximately equals ＞greater than ＜less than ≥ equal to or greater than ≤ equal to or less than >> much greater than << much less than ∈is a member of the set ( ) round brackets, parentheses [ ] square brackets { } braces ∽similar to ≌congruent to ⊥perpendicular to, at right angles with ∥parallel to ∠angle

⊙circle e the base o f natural logarithms, approx. 2. 71828 π pi; the ratio of the circumference of a circle to its diameter, diameter, approx, 3.14159 n! factorial n, n( n－1) ( n－2) (n－3) (1) ︱x︱the absolute value of x X2 raised to the second power X3 X cube; X cubed; the cube of X; X to the third power; the third power of X; X raised to the third power X-10 X to the minus tenth( tenth power) √x the square root of x 3√x the cube root of x X n the nth power of X, X to the power n, X raised to the nth power, X to the nth power 1/X n one over X to the n α 5/β2 α to the five over β squared X1/n(n√X) the nth root of X, X to the power one over n y=f(x) y is a function of x a+b a plus b; the sum of a and b; the total of a and b; a added to b; a increased to b; a increased by b; a more than b; a greater than b a－b a minus b; a less b the difference of a and b; from a subtract b; a takes away b; a decreased by b; a diminished by b; b is

曼哈顿FOV笔记

曼哈顿FoV. CR笔记目录 1.All about the Argument (1) Sound argument vs. valid argument (1) On the GMAT (2) The arguer’s job and your job (2) List of the twelve flaws (2) Details of the twelve flaws (3) A. Unjustified Assumptions (3) B. Causation Errors (4) C. Comparison Errors (5) D. Math Errors (6) E. Communication Errors (7) Find the gaps in arguments (7) 2.Decoding the Question Stem and Stratege (8) 1. All about the Argument Sound argument vs.valid argument Every complete argument has two components written down on paper: ? Premises—supporting statements ? Conclusion— the main point or biggest claim of the argument A sound argument is successful on every level: the premises are true, and the conclusion logically follows from the premises. When a conclusion follows logically from true premises, that conclusion is therefore true. A valid argument is one in which the conclusion follows logically from the premises—but the premises may or may not be true. In a valid argument, if the premises are true, then the conclusion will also be true. In a good, valid argument, the premises lead to the conclusion in a direct way. They provide enough evidence to guarantee the truth of the conclusion (which is occasionally implied rather than stated explicitly).

GMAT数学机经语法MATH1-277纯题目版

纯题目打印版 1. 11个数的mean 是50，从大到小排列，前6个的mean 是44，后6个的mean 是57，求median ？ 2. 已知f(n)=x ＋x n+1＋x n+2＋x n+3，当x=－1时，n is the sum of 404 prime integers ，求n ？【变题v1】X=-1, n 是前440个质数的和，问X+X^n+X^(n+1)+X^（n+2）=？ 3. DS ：梯形ABCD 由一个平行四边形和一个等腰三角形组成，问三角形CDE 的面积？81题变体（1）已知四边形ABCE 的面积（2）四边形AFEC 的面积是5 4. 已知n 是负整数，排列大小：2n ，－2n ，2－n ，n ，－2－n 5. 一个等腰三角形，一个边长等于5，一个边长等于6，问是否能判断第三个边长？（1）（2）面积等于12 【V2】一个三角形，一个边是5，一个边是10，问第三个边是多少？（1）边长是5的倍数（2）三角形是等腰三角形 A B C D E F

6. DS: 一个帐篷的形状（截面是一个等腰三角形，腰S ，底b, 高h ）求h 1）b=4 2）S=5 7. 某人出门向东走一段，然后向北走一段。向北走3mile 后休息一下，问当这个人和他家的直线距离是10mile 时，他休息后又走了多少mile ？（1）他休息时和家的距离是a （已知）（2）他向东走了4 mile 8. 5个苹果，有一个坏的，4个好的，从里面抽2个，抽中坏的的概率是多少？【V2】20个碗，已知其中一个是坏的，抽取2个碗，问抽到坏的的概率？ 9. 一个坐标轴，给出f(x)=x 2＋2 在第一象限的图，求抛物线和x=2，x=3，和x 轴围成的梯形的面积？ 10. U 是所有实数的集合，B 是大于1的实数集合，C 是大于4的实数集合，D 是小于5的实数集合，A 是大于n 得实数集合，是否能确定n 的值？ S b h 1

GMAT语法知识点归纳

OCEAN的语法知识点总结 By Roxas605（ChaseDream）资料来源：OG12、OG12-verbal、OG10、Prep07、Prep08、GWD、Manhattan 一、独立主格总结：独立主格只做状语，放在句首或句尾，表示伴随原因、条件、状态、目的、时间、补充说明等 ●独立主格三种形式： 1)一般形式：n.+n.，n.+V-ed/v-ing，n.+介词短语/形容词短语独立部分与主句部分无太多关联 2)with形式：with+宾语+宾补，如：with+n.+v-ed/v-ing/介词短语/形容词短语与主句主语有紧密的逻辑关系 3)each形式：each+v-ed/v-ing/介词短语/形容词短语；each+n.+介词短语必须前面有复数名词 *：with型独立主格在GMAT中常常被判累赘 ●另外，存在一种with+n.+/with+n.+定语从句,可以看做概括性同位语分析：放在句首，一定修饰主语，放在句尾既可以修饰主语也可以修饰谓语二、同位语总结：类似定语，修饰名词或者名词短语、代词（不是核心词指代） 1)名词性同位语：名词解释名词。（以下三种，第二个n.后可以跟修饰词） i.N., n.; ii.n., a/an + n.或a/an + n., n.; iii.the + n., n.（前面的the + n 为同位结构） 2)内容具体化同位结构：抽象名词（theory/evidence/belief/principle）+that 从句 that从句对抽象名词进行具体化解释（注意与of 结构的区别），that从句部分才是同位语。(that是小品词，连词，和一般的名词性that分句中的that一样) 3)概括性同位语：短语/句子，n. + that / doing / done... （+doing、done形式和独立主格相同）用一个概括性的名词去概括前面的修饰对象： ※同位语和独立主格的区别： 1. 同位语修饰名词，独立主格修饰句子 2.同位语表示前面名词的具体内容和特征，而独立主格是一种伴随状态，描述与伴随分局同步发生的事情（原因、条件）

GMAT语法笔记

GMAT语法笔记 May 18, 2013 综述 Gmat语法在verbal中是最重要的部分，16/41。是最严格的美式书面英文。做题时间1:10/Q 规律性强比如：maybe一定错，一般改为probably , perhaps。因为maybe是口语词，但是may be不一定错，may be 不是口语词。句式复杂，难句多，考法新是最严格的美式书面英文 Eg. 1）表“建议”suggest that S（subject,主语）should V-原型这是虚拟语气的句型表“建议”或“命令”的词（suggest, order, demand, mandate, require, insist, dictate, propose, recommend, stipulate）后，跟的从句should+V-原型，should必须省! 【注】suggest表“暗示”的时候，不是虚拟语气 2）team, family, group, army等这些词全部是单数，用is。 99%的名词只要加了s就是可数名词，少数1%如某种疾病diabetes:糖尿病。 3）定语从句that可以指人，也可以指物，但是Gmat考试中that只可以指物，不能指人，因为人要用who。五种简单句 1）SV 主语+动词 2）SCP 主系表 3）SVO 主谓宾 4）SVOO 主谓双宾 Eg. Tom gave Jerry a book. Tom advises Jerry that the movie (should) start early. 错！没有advice sb that, 只有tell, persuade, convince,这三个词可以+ sb that SVO(SVO表从句)，其他的单词均不能用+sb that的结构，同时这三个单词不能直接+that,且这三个词可以用自己的固定搭配Eg. Persuade sb to do sth或persuade sb into doing. 5）SVOC 主谓宾宾补 Eg.We call him Tom I think I love you. 错！that宾语从句的that在句中不能省略，但是是相对错，因为一般 say that中的that都省略。 LIKE

曼哈顿语法笔记讲解学习

Chapter 3: 主谓一致注意主语和谓语之间构成的逻辑意义相符合 Wrong: The development of a hydrogen car based on expected performance parameters will be able to travel hundreds of miles without refueling. Right: Once developed, a hydrogen car based on expected performance parameters will be able to travel hundreds of miles without refueling. 主语谓语之间必须做到单复数相符合 Eliminate the middlemen and Skip and warmup (准确做到正常的跳读) 没有必要的句子成分尽量少读介词短语，从句，其他修饰成分善于利用句子的机构去判断单复数 The tidal forces to which an object falling into a black hole is subjected are sufficient to tear the object apart. And和additive phases （注意mathematics，aerobics，diabetes,citus都是单数的形式） Media是medium的复数形式。 Either or（就近原则确定谓语单复数）集体名词 People: agency, army, audience, class, committee, crowd, orchestra, team Items: baggage, citrus, equipment, fleet, fruit, furniture. 用单数 Our army of a hundred thousand soldiers is attacking the enemy. 不定代词 SANAM：some, any, none, all, more/most 这几个词语要依据不同情形确定单复数 Any of these women is a suitable candidate for marriage to my son. Not one of my friends is here this weekend. Every and each Every dog has paws. Every dog and cat has paws.

GMAT数学概率知识点解析

GMAT数学概率知识点解析概率，又称或然率、机会率或机率、可能性，是数学概率论的基本概念，是一个在0到1之间的实数，是对随机事件发生的可能性的度量，概率是GMAT中比较常见的考点，接下来小编就GMAT 数学概率为大家介绍一下，助力考生顺利备考GMAT数学考试。一.抽样： (一)不可放回：sampling without replacement 1. 一次性抽取：T12，T17，T19，T22，T23，T24，T46 2. 依次抽取抽取： (1)第k次抽到的概率：T36 (2)抽奖问题： Eg：10张彩票，有一张奖票，人们依次抽出，则每个人中奖的概率相同。 1st：P=1/10 2nd: P=9/10 * 1/9 3rc: P=9/10 * 8/9 * 1/8 (3)几何概率(用面积或时间长度)：T14 (4)其他：T16，T17， T25，T26，T31(综合：体现分类抽取与一次性抽取的转换) (二)可放回：sampling with replacement Eg：10张彩票，2张奖票，重复抽样，一个人连续重复抽样3次，每次都中奖的概率？

(三)其他：T13，T15 二.伯努利概型：【前提】：独立重复试验三.涉及排列组合的：T20，T21(捆绑)，T34，T35 四.其他：T28，T29(注意两个事件是否相互独立的判断)，T30(条件概率)，T18(条件概率)，T50(容易忽略是2种情况) 以上就是关于GMAT数学概率的相关内容介绍，希望大家能够了解。多多备考了解GMAT相关信息，争取做到万无一失。更多关于GMAT数学考试知识点的介绍小编会为大家呈现。最后祝大家顺利备考GMAT考试，早日梦圆名校。

GMAT SC Manhatten曼哈顿语法总结(770NN)

目录 Subject-verb agreement (7) Fragment: Subject and verb must both exist (7) Sense: Subject and verb must make sense together (8) Number agreement: Subject and verb must agree in number (9) Additive phrases (9) Or, either…or, neither…nor: nearest . 9 Collective nouns: almost always singular (9) Indefinite pronouns: usually singular.9 SANAMM words: some; any; none; all; more; most; (9) Each and every (9) Quantity words and phrases (9) Subject phrases and clauses: always singular (10) Parallelism (10) Parallel markers (10) Parallel elements (11) You can split apart the expressions:.. 12 Parallel clauses should start with the same word (12) Lists with AND (13) Idioms with parallel structure (13) Superficial parallelism vs. actual parallelism (13) Watch out for linking verbs (14)

GMAT数学六大思想

数学六大思想 1）分类讨论思想所谓分类讨论，就是当问题所给的对象不能进行统一研究时，我们就需要对研究的对象进行分类，然后对每一类分别研究，得出每一类的结论，最后综合各类的结果得到整个问题的解答.实质上分类讨论是“化整为零，各个击破，再积零为整”的策略. 分类讨论时应注重理解和掌握分类的原则、方法与技巧、做到“确定对象的全体，明确分类的标准，分层别类不重复、不遗漏的分析讨论.” 例题： How many different prime numbers are factors of the positive integer n? (1)Four different prime numbers are factors of 2n (2)Four different prime numbers are factors of n2 分析：(1) 2n有四个不同的质因数。由于2n中含有2这个系数，因此n中是否有2便成为了解题的关键。当n中含有2时，假设2n=2*2*3*5*7，此时2n含有4个不同的质因数，满足条件，而n也含有四个不同的质因数(2、3、4、5)；而当n中不含2 时，假设2n=2*3*5*7,此时2n含有四个不同的质因数，而n含有3个不同的质因数(3、5、7)。因此对于(1)来说，答案不唯一，因此不充分。 (2) n2有四个不同的质因数就避免了(1)中出现的问题，假设n2=2 2325272，则n便含有四个不同的质因数(2、3、5、7) 因此(2)是充分的，此题选B 2）转化与化归思想所谓转化与化归思想方法，就是在研究和解决有关数学问题时，采用某种手段将问题通过变换使之转化，进而达到解决的一种方法.一般总是将复杂的问题通过转化为简单的问题，将难解的问题通过变换转化为容易的问题，将未解决的问题变换转化为已解决的问题. 转化与化归的思想方法是数学中最基本的思想方法.数学中一切问题的解决都离不开转化与化归，数形结合思想体现了数与形的相互转化；函数与方程思想体现了函数、方程、不等式间的相互转化；分类讨论思想体现了局部与整体的相互转化，以上三种思想方法都是转化与化归思想的具体体现.各种变换法、分析法、反证法、待定系数法、构造法等都是转化的手段.所以说转化与化归是数学思想方法的灵魂. 例题： If zy＜xy＜0, is │x-z│+│x│=│x-z│? (1) z＜x (2) y＞0 分析：解：条件1 z＜x 转化为z-x＜0 zy＜xy＜0转化为zy-xy＜0，进一步转化为y(z-x) ＜0 上述2个不等式联立，可推导出y＞0 所以条件1和条件2其实是一样的，分别充分答案D ，条件1和条件2分别充分 DS题常常需要用到转化与化归。陷阱往往就出在，2个看似不同的条件，转化后其实是相同的。没有注意到这一点，就容易误选。

【小站教育】GMAT数学笔记

https://www.sodocs.net/doc/6e4767709.html, GMAT数学笔记 GMAT 数学备考关键词一、知识点：准确掌握二、词汇、表达法：读懂题目三、熟练：平均两分钟一道题考试相关问题一、时间与题量二、题型三、机经与换题库四、其它 If a and b are positive integers such that a –b and a/b are both even integers, which of the following must be an odd integer? （A）a/2 （B）b/2 （C）(a+b)/2 （D）(a+2)/2 （E）(b+2)/2 If M is the least common multiple of 90, 196, and 300, which of the following is NOT a factor of M? (A) 600 (B)700 (C) 900 (D) 2,100 (E) 4,900 复习注意事项 *战略上重视 *初等数学的思维 *解法力求稳妥清晰 *把握好DS 题型 *熟练重于技巧推荐复习步骤 *知识点查缺补漏 *背熟词汇 *复习课上所学 *OG，及其它相关资料 *机经：https://www.sodocs.net/doc/6e4767709.html,

https://www.sodocs.net/doc/6e4767709.html, 第一章算术 1. integer (whole number): 整数 * positive integer：正整数，从1 开始，不包括0。 2. odd & even number 奇数与偶数 * 凡整数均具有奇偶性，如－1 是奇数，0 是偶数。 * 奇+奇=偶，奇+偶=奇… 若干个整数相乘，除非都是奇数，其乘积才会是奇数… 例：If a and b are positive integers such that a –b and which a are both even integers, b of the following must be an odd integer? (A）a (B）b (C)a +b (D) a + 2 (E) b + 2 2 2 2 2 2 3. prime number & composite number 质数与合数 * A prime number is a positive integer that has exactly two different positive divisors,1 and itself. * A composite number is a positive integer greater than 1 that has more than two divisors. * The numbers 1 is neither prime nor composite, 2 is the only even prime number. 4. factor(divisor) & prime factor 因子和质因子 * 一个数能被哪些数整除，这些数就叫它的因子（因数、约数）。 * 因子里的质数叫质因子（数）。例1：If n=4p, where p is a prime number greater than 2, how many different positive even divisors does n have, including n? (A) 2 (B) 3 (C) 4 (D) 6 (E) 8 例2：If the integer n has exactly three positive divisors, including 1 and n, how many positive divisors does n2 have? (A) 4 (B) 5 (C) 6 (D) 8 (E) 9 例3：1225 有几个因子？例：What is the greatest prime factor of 2100 - 296? (A) 2 (B) 3 (C) 5 (D) 7 (E) 11